How Do You Calculate the Tension in Cables Suspending a Loudspeaker?

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SUMMARY

The tension in the cables suspending a 20kg loudspeaker, positioned 2m below the ceiling with two 3m long cables angled outward, is calculated to be 147N. The weight of the loudspeaker is determined using the equation w=mg, yielding a weight of 196N. To find the tension, it is essential to analyze the forces acting on the loudspeaker by breaking them down into components, considering that both cables experience equal tension due to their symmetrical arrangement.

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Homework Statement


A 20kg loudspeaker is suspended 2 m below the ceiling by two 3m long cables that angle outward at equal angles. What is the tension in the cables?


Homework Equations





The Attempt at a Solution


cos theta = 2/3, theta=48.2 degrees
w=mg=20kg * 9.8m/s^2 = 196N

But the answer is 147N
 
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Try drawing a FBD and see what the forces tell you.
 
Last edited:
w=mg=20kg * 9.8m/s^2 = 196N

You have to break this problem down into components in order to solve it.

Hint: Since the angles are the same, the tension in both cables will be the same.
 

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