How Do You Calculate the Time and Speed of a Falling Object?

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SUMMARY

The discussion focuses on calculating the time, speed, and distance of a falling object, specifically a stone dropped from a height of 51.2 meters. Using the acceleration due to gravity (g = 9.8 m/s²), the time to reach the ground is calculated using the equation t = √(2h/g), resulting in approximately 3.2 seconds. The speed just before impact is determined using v = gt, yielding around 31.36 m/s. The distance fallen during the last second is calculated using the formula for distance in the last second, resulting in approximately 4.9 meters.

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aussierad
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Hey guys,
Just wondering if you could please help me decode this question as well as put a little explanation as to how you got that answer. I am really struggling to get the correct calculations

(Take g = 9.8 m.s -2)

A stone is dropped from a height of 51.2 metres from the ground.
(a) How long does it take to reach the ground?
(b) What speed just before it strikes the ground?
(c) How far does it fall during the last second of it's fall?


Thanks!
 
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