How Do You Calculate the Total Energy of a Rolling Sphere?

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Homework Statement



A solid sphere of mass 0.599 kg rolls without slipping along a horizontal surface with a translational speed of 5.31 m/s. It comes to an incline that makes an angle of 33° with the horizontal surface. Neglect energy losses due to friction.


(a) What is the total energy of the rolling sphere?
________ J
(b) To what vertical height above the horizontal surface does the sphere rise on the incline?
________ m


Homework Equations



?

The Attempt at a Solution



What equations would I use for this problem? any other information would be great thanks!
 
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Kinetic energy is given by [tex]K=\frac{1}{2}mv^2[/tex]

Rotational energy is given by [tex]T=\frac{1}{2}I\omega^2[/tex]

The moment of intertia for a solid sphere is given by [tex]I=\frac{2}{5}mr^2[/tex]

Potential energy is given by [tex]U=mgh[/tex]
 
You will need one more equation to solve this.

[tex]v=\omega r[/tex]
 
Some hints from a fellow learner:

- How do you calculate linear (aka translational) movement energy for a body?
- What is the difference between kinetic and potential energies and how do you calculate them?
- Is energy conserved, if there is no friction or drag (aka energy losses)?