How Do You Calculate the Total Entropy of a Helium Balloon?

  • Thread starter Thread starter Gemstone
  • Start date Start date
  • Tags Tags
    Entropy Gas
Click For Summary
SUMMARY

The total entropy of a helium balloon can be calculated using the principles of thermodynamics and the ideal gas law. Given 10 moles of helium at an initial temperature of 298 K and a final temperature of 268 K, the entropy change can be derived from the first law of thermodynamics and the equation for ideal gases, PV = nRT. The relevant formulas include S = kLn(Ω) and ∆S = ∫dQ/t, which are essential for calculating the entropy change during the transition from one temperature to another.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Familiarity with the first law of thermodynamics (dE = -PdV + TdS)
  • Knowledge of entropy definitions (S = kLn(Ω) and ∆S = ∫dQ/t)
  • Basic principles of thermodynamics and statistical mechanics
NEXT STEPS
  • Research the derivation of entropy change for ideal gases
  • Study the first law of thermodynamics in detail
  • Explore the statistical mechanics definition of entropy
  • Learn about the application of thermodynamic principles in real-world scenarios
USEFUL FOR

Students in physics or chemistry, particularly those studying thermodynamics, as well as anyone interested in understanding the principles of entropy in ideal gases.

Gemstone
Messages
2
Reaction score
0
Me and a friend has recently fallen into a dead-end with an assignment we have, because we can't calculate the total entropy of a balloon filled with Helium.

basically, the assignment goes:
We have a balloon with 10 mol of Helium, inside a house with a temperature of 25 degrees celsius (that is, 298 kelvin). Now, we take the balloon outside to a temperature of -5 degrees clecius (268 kelvin).

Now, we're supposed to calculate the total entropy of the balloon and the environment. Anyone willing to help us out?

We've this far deducted that the pressure is 101,3 KPa (1 atmosphere)... which is by far the longest we've come.

Any help is appreiciated
 
Physics news on Phys.org
Entropy is:

S=kLn(Ω)

Where Ω is the multiplicity of the system.

Also. ∆S=∫dQ/t

This should help get you started.
 
I think starting from the statistical definition of entropy would be a bit much for this problem. =P I think the formulae for ideal gases are well known enough that they can just be used right from the start.

So, since you're dealing with helium, you can indeed treat the gas in the balloon as an ideal gas.

Start with the first law: dE = -PdV + TdS

For an ideal gas, you know how pressure and volume relate: PV = nRT, and there's also a formula for the energy of an ideal monatomic gas, E = 3nRT/2. From this you can derive an equation for the entropy change given the volume change and the temperature change (recall that in these formulae temperature must be measured in Kelvins).

Hopefully that helps.
 
Thank you for your help :) We managed to solve the equation in the end
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 6 ·
Replies
6
Views
688
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
8K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
12K
  • · Replies 1 ·
Replies
1
Views
9K
Replies
7
Views
3K
Replies
1
Views
10K
Replies
1
Views
2K