How Do You Calculate the Volume Between a Cone and a Sphere?

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Homework Help Overview

The problem involves calculating the volume of a solid that lies above a cone defined by Φ = π/3 and below a sphere described by ρ = 4cosΦ. The context is set within spherical coordinates, where participants are exploring the bounds for the triple integral necessary for the volume calculation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the appropriate bounds for ρ, questioning why it starts at 0 when the solid is above the cone. There is an exploration of the relationship between the cone and the sphere, with attempts to clarify the definitions of the spherical coordinates involved.

Discussion Status

The discussion is ongoing, with participants providing clarifications on the definitions of the variables and the nature of the cone and sphere. Some guidance has been offered regarding the interpretation of the problem, but multiple interpretations and uncertainties remain regarding the graphical representation and the bounds of integration.

Contextual Notes

There is mention of different conventions in defining spherical coordinates, which may contribute to the confusion regarding the setup of the problem. Participants are also grappling with how to accurately visualize the scenario described in the problem statement.

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Homework Statement



Find volume of the solid that lies above the cone Φ = π/3 and below the sphere ρ = 4cosΦ

Homework Equations

The Attempt at a Solution



Obviously this is a triple integral. My book tells me that 0 ≤ρ≤ 4cosΦ

but this makes no sense to me.

From the problem, it lies ABOVE the cone Φ = π/3 and below the sphere ρ = 4cosΦ, so wouldn't that imply that ρ is not starting at 0?

What I did was solved ρ = 4cosΦ

arccos(ρ/4) = Φ and set it = to pi/3

arccos(ρ/4) = π/3

ρ/4 = cosπ/3

ρ = 4 * (1/2) = 2

so wouldn't 2≤ρ≤4cosΦ be the bounds? I don't understand how the lower bound can start at 0 when its asking for what's above the cone and below the sphere..
 
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Rijad Hadzic said:
wouldnt that imply that ρ is not starting at 0?
No. Also, please define your variables.

I suggest you draw an image of what things look like.
 
Orodruin said:
No. Also, please define your variables.

I suggest you draw an image of what things look like.

ρ is the distance to the point from the origin
Φ is the angle from the z axis to the point. 0≤Φ≤pi
θ is the angle to the point from the projection in the xy plane.

I did draw an image, it looks like an icecream cone basically. The part I want is the icecream on the top of the cone. I still don't understand why ρ is 0..
 
Hmm I think I may be graphing it wrong. Maybe I have no clue how to graph ρ = 4cosΦ..
 
Rijad Hadzic said:
ρ is the distance to the point from the origin
Φ is the angle from the z axis to the point. 0≤Φ≤pi
θ is the angle to the point from the projection in the xy plane.
Different textbooks treat spherical coordinates in different ways, particularly the ##\theta## and ##\phi## coordinates. According to this wikipedia article (https://en.wikipedia.org/wiki/Spherical_coordinate_system), physics books consider ##\phi## to be the angle in the "x-y" plane, while math textbooks consider ##\phi## to be measured from the positive z-axis.
 
Rijad Hadzic said:
The part I want is the icecream on the top of the cone.
No, this is not correct. The "cone" that the problem talks about is the mantle surface of the cone. If it was just the top that was intended, the problem would talk about a plane, not about a cone.
 

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