How Do You Calculate Time and Distance for Deceleration in Physics?

Click For Summary
SUMMARY

The discussion focuses on calculating time and distance for a particle decelerating according to the equation a = -kv, where k is a constant. Given an initial velocity v0 = 4 m/s and a velocity of v = 1 m/s at t = 2 s, the time T for the particle's speed to reduce to one-tenth of its initial value is determined to be T = 3.32 s, with the corresponding distance D calculated as D = 5.19 m. The solution involves integrating the acceleration equation to express velocity as a function of time.

PREREQUISITES
  • Understanding of basic calculus, specifically integration techniques.
  • Familiarity with the concepts of acceleration and velocity in physics.
  • Knowledge of logarithmic functions and their properties.
  • Ability to solve differential equations related to motion.
NEXT STEPS
  • Study the integration of differential equations in physics contexts.
  • Learn about the application of exponential decay in motion problems.
  • Explore the relationship between acceleration, velocity, and time in kinematics.
  • Practice similar problems involving deceleration and integration techniques.
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and motion equations, as well as educators looking for instructional examples in calculus applications in physics.

Mobz
Messages
2
Reaction score
0

Homework Statement



A particle moving along a straight line decelerates according to a= -kv, where k is a constant and v is velocity. If its initial velocity at time t=0 iv v0=4 m/s and its velocity at time t=2 s is v = 1 m/s, determine the time T and corresponding distance D for the particle speed to be reduced to one-tenth of its initial value

ans T = 3.32 s, D = 5.19 M



Homework Equations





The Attempt at a Solution



I have never tried a problem like this.. I just need some instruction on how to start.

Thanks you very much!
 
Physics news on Phys.org
Mobz said:

Homework Statement



A particle moving along a straight line decelerates according to a= -kv, where k is a constant and v is velocity. If its initial velocity at time t=0 iv v0=4 m/s and its velocity at time t=2 s is v = 1 m/s, determine the time T and corresponding distance D for the particle speed to be reduced to one-tenth of its initial value

ans T = 3.32 s, D = 5.19 M

Homework Equations



The Attempt at a Solution



I have never tried a problem like this.. I just need some instruction on how to start.

Thanks you very much!

Welcome to PF.

Notice first your equation a = -kv expresses Acceleration as a variable in V.
Hence to develop an equation expressing V as a function of t you will need to integrate a which is dv/dt. Rearranging your equation you have then:

1/v*dv = -k*dt

Integrating you get something of the form:

ln|v| = -k*t + c

You can use the values given to determine the constants of the equation.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
20
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
3
Views
2K
Replies
8
Views
6K
  • · Replies 38 ·
2
Replies
38
Views
4K