How Do You Calculate Trip Duration and Distance with Stops and Average Speed?

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SUMMARY

The discussion focuses on calculating trip duration and distance when accounting for a rest stop. A person drives at a constant speed of 90.5 km/h, with a 22-minute rest stop, resulting in an average speed of 73.4 km/h. The relationship between distance, speed, and time is established using the formula v = d/t. The key equation derived is 90*t = 73.4*(t + 22/60), allowing for the calculation of total trip time and distance traveled.

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  • Ability to apply the average speed formula in practical scenarios
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This discussion is beneficial for students studying physics, educators teaching motion concepts, and anyone interested in practical applications of speed and distance calculations in travel scenarios.

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Homework Statement


A person takes a trip, driving with a constant speed of 90.5 km/h except for a 22.0 min rest stop. If the person's average speed is 73.4 km/h, how much time is spent on the trip and how far does the person travel?


Homework Equations


v = d/t


The Attempt at a Solution


I have no idea how to solve this, other than that I have to plug the values into the average speed formula.
 
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aquapod17 said:

Homework Statement


A person takes a trip, driving with a constant speed of 90.5 km/h except for a 22.0 min rest stop. If the person's average speed is 73.4 km/h, how much time is spent on the trip and how far does the person travel?

Homework Equations


v = d/t

The Attempt at a Solution


I have no idea how to solve this, other than that I have to plug the values into the average speed formula.

From your equation you know that d = V*t

If you hadn't stopped you know that 90.5*t is the distance
But you did stop 22 minutes (which is 22/60 hours) so to do the same distance it was 73.4*(t+22/60)

Since the distance is the same then 90*t =73.4*(t+22/60)

I'm sure you get the idea from here.
 

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