How Do You Calculate Turns and Current in an Ideal Transformer?

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SUMMARY

The discussion focuses on calculating the primary and secondary turns, cross-sectional area of the core, and full load current in a 4.4kVA 440V/4400V step-up transformer. The primary turns are determined to be 44, while the secondary turns are 440, based on the induced emf per turn of 10V. The full load current is calculated as 10A for the primary and 1A for the secondary. The lack of a specified frequency in the problem is noted as a potential issue, with participants suggesting an assumption of either 50Hz or 60Hz for calculations.

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Homework Statement



The Mag FLux Density in the core of a 4.4kVA 440V/4400V step up TX is 0.8T (rms). If the induced emf per turn is 10V, find: a) the primary and secondary turns, b) The cross sec area of the core, c) the full load current in each winding.

Homework Equations






The Attempt at a Solution



part a isn't hard, as this question is in a chapter dealing with ideal transformers and so The total emf induced is the same as the applied voltage. The Number of primary turns can therefore be deduced by;

Total emf induced/emf per turn = 440/10 = 44 turns in primary,

this can then be done again for the secondary and the resulting value for number of secondary turn is 440.

For the third part, I believe that the primary current = VA/V1 = 4400VA /440V = 10A, anf the secondary current = VA/V2 = 4400VA / 4400V = 1A. This would make sense based on all the above calculations for turns etc.

I would like some help with the second part of the equation, as i cannot understand how it can be solved using the emf equations for a single phase transformer, as there is no frequency given??

Thanks
 
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Physicist3 said:

Homework Statement



The Mag FLux Density in the core of a 4.4kVA 440V/4400V step up TX is 0.8T (rms). If the induced emf per turn is 10V, find: a) the primary and secondary turns, b) The cross sec area of the core, c) the full load current in each winding.

Homework Equations






The Attempt at a Solution



part a isn't hard, as this question is in a chapter dealing with ideal transformers and so The total emf induced is the same as the applied voltage. The Number of primary turns can therefore be deduced by;

Total emf induced/emf per turn = 440/10 = 44 turns in primary,

this can then be done again for the secondary and the resulting value for number of secondary turn is 440.

For the third part, I believe that the primary current = VA/V1 = 4400VA /440V = 10A, anf the secondary current = VA/V2 = 4400VA / 4400V = 1A. This would make sense based on all the above calculations for turns etc.

I would like some help with the second part of the equation, as i cannot understand how it can be solved using the emf equations for a single phase transformer, as there is no frequency given??

Thanks

You have to assume a frequency. Probably 60 Hz. Good point!
 
rude man said:
You have to assume a frequency. Probably 60 Hz. Good point!

This is what I thought, but obviously there are two feasible frequencies that could be used (50Hz or 60Hz), so the accuracy of the answer will therefore be affected. I hate it when textbooks don't give answers to their questions!
 
Physicist3 said:
This is what I thought, but obviously there are two feasible frequencies that could be used (50Hz or 60Hz), so the accuracy of the answer will therefore be affected. I hate it when textbooks don't give answers to their questions!

Agreed! Where was your textbook published? That might offer a clue as to the intended frequency. What about context (the chapter associated with the problem)?
 

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