How Do You Calculate Velocity and Acceleration in a Belt and Pulley System?

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In a belt and pulley system with three belts and two pulleys, the input belt at point A moves at a constant speed of 0.6 m/s. The angular velocity of the pulleys is calculated to be 6 rad/s in the clockwise direction. The velocity at point C on the output belt is assumed to be 0.3 m/s, while the acceleration at point B on the output pulley is considered to be 0. The calculations and assumptions regarding the system's dynamics are questioned for accuracy. The discussion emphasizes the need for clarity in determining the velocity and acceleration in such mechanical systems.
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Homework Statement



Three belts move over two pulleys without slipping in the speed reduction system. Point A on the input belt moves to the right with a constant spped of 0.6m/s. Determin the velocity of point C on the output belt, and the acceleration of point B on the output pulley.

Homework Equations



Va = Vo + wr
where Vo is the velocity of center of left pulley which is equals to 0m/s
so Va = wr

The Attempt at a Solution



with the above equation I found out that the angular velocity of the pulley is
0.6m/s = (0.1)w
w = 6rad/s clockwise direction
and this means that the pulley is rotating with the speed of 6 x radious of bigger part of pulley = 0.6m/s and from the picture we can deduce that the pulley on the left also rotating with same speed.
This is my assumption and i don't think this is right, and even though this is right how can i find the Vc and acceleration at point B?
 

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is Vc = 0.3m/s
and acceleration at point B = 0?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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