How Do You Calculate Work in a Reversible Ideal Gas Cycle?

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    Diagram Pv=nrt
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SUMMARY

This discussion focuses on calculating work done in a reversible ideal gas cycle involving one mole of an ideal gas at an initial temperature of 300K and pressure of 4 atm. The cycle consists of four distinct processes: isothermal expansion, isothermal compression, isothermal compression to a specified pressure, and constant pressure expansion. Key equations utilized include the ideal gas law (PV=nRT) and work calculation (W=-P(delta)V). The discussion emphasizes the need for unit conversion from atm to Pa for accurate calculations and the importance of using external pressure in work calculations during reversible processes.

PREREQUISITES
  • Understanding of the ideal gas law (PV=nRT)
  • Familiarity with thermodynamic processes (isothermal, isobaric)
  • Knowledge of work calculation in thermodynamics (W=-P(delta)V)
  • Ability to convert units (atm to Pa)
NEXT STEPS
  • Learn about reversible processes in thermodynamics
  • Study the derivation and application of the ideal gas law
  • Explore graphical representation of thermodynamic cycles on PV diagrams
  • Investigate the concept of external pressure in work calculations
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone involved in engineering or physical sciences who seeks to understand the principles of work in ideal gas cycles.

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Homework Statement


One mole of an ideal gas at an inital tempreature of 300K and pressure of 4 atm is carried through the following reversible cycle:

a) It expands isothermally until its volume is doubled.
b) It is compressed to its original volume at constant temperature.
c) It is compressed isothermally to a pressure of 4 atm.
d) It expands at constant pressure to its original volume

Make a plot of this cycle process on a PV diagram and calculate the work done by the gas per cycle.

Homework Equations


PV=nRT
PV/T = PV/T
W = -P(delta)V
H = 5/2RT
(delta)U = Q + W

The Attempt at a Solution


So I started off by finding the original volume.
V = nRT/P
V = (1 mole)(8.31 constant)(300 degrees Kelvin) / 4(1.013x10^5)
V = 0.0062 cubic meters.

Then for step (a), since it expands isothermally, PV must remain constant as well as T. W = P(delta)V. Since it's a constant, I can just multiply 4.013x10^5 by 0.0062. That gives me 2512.24 joules. It's positive because it's expanding.

This next part is where I get stuck. If the volume is compressed back to its original volume, that means pressure has to go back to its original as well since the temperature is constant, the number of moles can't change, and neither can a constant. What do I do for this step and the other 2?

Also, how would I draw the diagram?


Question 1: Is it correct to multiply 4 by 1.013x10^5 because our PV=nRT equation is not in atm and we need to convert it?
 
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Regarding your question in red, it's all in the units.
R=8.314\frac{J}{K mol}=8.314\frac{m^3 Pa}{K mol}
So yes, you do need to convert from atm to Pa if you want to use R=8.314. Alternatively, you could use R=0.08206 L*atm / K*mol, leave P in atm and your volume would then be in L.

And I'd reconsider part (a). Remember - this is a reversible expansion. And technically dW=-Pext dV, where Pext is the external pressure the gas is expanding against. W=-P\DeltaV only applies when Pext is constant.
 
Last edited:
Wait, I'm still confused. I've never done any of this before because my teacher doesn't teach and he sprung this on us within two days of the section. How would I figure out the work then for each part? How would I draw the diagram?
 

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