How do I convert a repeating decimal from one base to another?

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Homework Help Overview

The discussion revolves around converting repeating decimals between different bases, specifically from base 4 to base 10 and vice versa. Participants explore the mathematical principles involved in these conversions, particularly focusing on geometric series and their applications in different numeral systems.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the representation of repeating decimals as geometric series and question the application of the geometric series formula. There is uncertainty about the correct values for the first term and common ratio in the context of base conversions.

Discussion Status

The conversation is ongoing, with participants sharing insights and questioning each other's reasoning. Some have offered alternative methods and interpretations, but there is no explicit consensus on the correct approach or final answer.

Contextual Notes

Participants express confusion regarding the application of formulas and the representation of numbers in different bases. There is mention of potential errors in the setup of the geometric series and the need for clarification on the conversion process.

srfriggen
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Homework Statement



1. Convert (0.333...)4to base 10.

2. Convert (0.333...)10to base 4.

Homework Equations



For question 1:


I see this can be written as (3/4+3/42+3/43...)10

Can I just use the geometric formula and arrive at the answer 12/3=4 ?

But that doesn't match, because 4 in base 10, written in base 4 is just 10.




For problem 2 I'm not sure how to start. There was a trick regarding division and keeping the remainder, but I'm not sure that applies to decimals.


The Attempt at a Solution


 
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hi srfriggen! :smile:
srfriggen said:
I see this can be written as (3/4+3/42+3/43...)10

Can I just use the geometric formula and arrive at the answer 12/3=4 ?

yes, but doesn't your formula apply to 1 + 3/4 + … ? :wink:

(btw, doesn't that look a lot to you like 0.9999… ?)
For problem 2 I'm not sure how to start. There was a trick regarding division and keeping the remainder, but I'm not sure that applies to decimals.

you mean to quaternary? (quaternals?)

yes, long division works in any system :smile:
 
the series can be written as 3*10-1+3*10-2+3*10-3...

And isn't the formula for a geometric series: a(1/1-r)?

So here, a=3 and r=1/4, right?

When I plug in and multiply out I get an answer or 4, not .9...

What am I missing?
 
3*1 + 3*10-1+3*10-2+3*10-3...= a(1/1-r) :wink:
 
Wait, I wrote that out wrong, it's not:

he series can be written as 3*10-1+3*10-2+3*10-3...

those 10s should be replaced with 4s, right?


I'm still getting a=3 and r=1/4. Am I right with that?
 
a*(1 + b + b2 + b3) + … = a/(1 - b)

you left out the a*1 (= 3), which if you subtract from 4 is …? :wink:
 
so isn't the formula a=3 and b=1/4? If so that still give the answer or 4. I don't see where subtracting 3 comes into play.
 
your formula does not have an a*1 …

it starts with a*b :smile:
 
I'm looking at my book now and it says the formula is a(1/1-r). If a=3 and r=1/4, I get the answer to 4. I'm not sure what is wrong of the previous statement? Either my formula is wrong or my a and r choices are wrong.
 
  • #10
I'm sorry tiny tim I'm just not getting it today. I'm going to take a break, so some studying later, and come back to this one. Thanks for your patience so far!
 
  • #11
a*(1 + b + b2 + b3 + …) = a/(1 - b) = 3/(1 - 1/4) = 4

a*(b + b2 + b3 + …) = a/(1 - b) - a = ab/(1 - b) = 4 - 3 = 1
 
  • #12
ahhh, now I see what you meant by "your formula" !
 
  • #13
ok, alternative method: can you see that 0.33333 = 1 - 0.00000… ?

(ie you can't get any closer to 1 ! :wink:)
 

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