How Do You Convert Parametric Equations to Algebraic Form?

[Burr2]

X1 T = 10T

Y1 T = 100 + (.5 * -9.8T^2)

X2 T = 100 - 12.3 T

X2 T = 0

How do I put this into algebraic form? it seems easy but I just can't get it.

Do you simply add the X and Y components? If so what do x and y each stand for?? Does it have something to do with sine and cosine? =/

 

[rhuthwaite]

Are you needing to know how to put the equations together? Because there's a thing called derivatives of parametric equations in calculus.

for example
if x = t + t-1 and y = t + 1

dx/dt = 1 – t -2
= 1 – 1/t2
dy/dt = 1
Then dy/dx = dy/dt x dt/dx

Then you substitute in the equations and solve
If that’s what you are needing to solve your question just do the same thing for your parameters given.

 

[Mindscrape]

Think about this in terms of slope and the difference between two different points. In other words, as time increases, how much does x increase or decrease? How much does y increase or decrease?

 

[andrevdh]

I think the equations should read

$$x_1 (t) = 10t$$

$$y_1 (t) = 100 - \frac{1}{2}gt^2$$

$$x_2 (t) = 100 -12.3t$$

$$y_2 (t) = 0$$

so these equations describe the positional coordinates of two different objects as functions of time. What do you need to determine about the two objects?