How Do You Determine Reverse Saturation Current in Diode Circuits?

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SUMMARY

The discussion focuses on determining the reverse saturation current (IS) in diode circuits using various voltage values (VD) such as 0.6V, 0.65V, and 0.7V. Participants confirm that IS can be calculated for each specified VD by substituting known values into the equation ID = IS e(VD/0.0375). The use of Thevenin's theorem is also highlighted as a valid approach to simplify the circuit analysis. The discussion concludes that both nodal analysis and Thevenin's equivalent can effectively yield the desired results.

PREREQUISITES
  • Understanding of diode characteristics and reverse saturation current (IS)
  • Familiarity with Thevenin's theorem for circuit simplification
  • Knowledge of nodal analysis techniques
  • Basic grasp of exponential functions in the context of electronic equations
NEXT STEPS
  • Study the derivation of the Shockley diode equation for better comprehension of IS
  • Learn about Thevenin's theorem applications in more complex circuits
  • Explore the impact of temperature on reverse saturation current in diodes
  • Investigate graphical methods for analyzing diode characteristics, including load lines
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in semiconductor device analysis will benefit from this discussion.

chebyshevF
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Homework Statement


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Homework Equations


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The Attempt at a Solution


Just want to know whether I have the right idea: so to determine the reverse saturation current (IS), I just determine it for each value of VD that was given? So finding IS for 0.6, 0.65, 0.7 etc?

The question seems to be divided into two parts, one that just asks for the reverse saturation current, and then to sketch a graph for points VD=0.6, 0.65 etc. But it's not as if we're already given an initial VD value to determine the reverse saturation current, so I'm guessing you just find it for the various values given?

Thanks.
 
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- Replace the voltage source and resistors with a Thevenins equivalent.
- From the load line : Id = 6 - Vd (I in mA) you can find Vd.
- Sub the now known values of Vd and Id into Id = Is e^(Vd/0.0375) to find Is.

Note: Id and Is both mA in that equation. And yes it's ok to leave out the "-1".
 
Last edited:
Actually I already figured it out using nodal analysis, but thanks anyway. And I just tried using Thevenin's theorem, and it worked out too :)
 
Last edited:

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