How Do You Determine the Constant k for Level Curves in Piecewise Functions?

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SUMMARY

The discussion centers on determining the constant k for level curves in the piecewise function defined as f(x,y)=4 if x²+y²≤16 and f(x,y)=sqrt(32-x²-y²) if 16 PREREQUISITES

  • Understanding of piecewise functions
  • Knowledge of level curves in multivariable calculus
  • Familiarity with the equations of circles and spheres
  • Basic algebraic manipulation and graphing skills
NEXT STEPS
  • Explore the concept of level curves in multivariable functions
  • Study the properties of piecewise functions and their graphs
  • Learn about the implications of domain restrictions in piecewise definitions
  • Investigate the relationship between k values and function behavior in piecewise contexts
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Students studying multivariable calculus, educators teaching piecewise functions, and anyone interested in understanding level curves and their applications in mathematical analysis.

esmeco
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Hello!

Homework Statement



Well,I'm having a problem drawing level curves for piecewise functions.
The problem is, how do I know which value the constant k will hold?

Homework Equations



The functions is the following:

f(x,y)=4 if x^2+y^2<=16
sqrt(32-x^2-y^2) if 16<x^2+y^2<=32

The Attempt at a Solution



The solution I've attempted and which I'm not sure it's correct is:
I've drawn a level curve of level 4,because it's within the domain of f(x,y)(which is ]-infinity;32]) and it's the point where the function changes to the other branch.
Does this make sense?

Just another question,to determine the domain of the second "piece" of the function,why do we also use the sqrt(32-x^2-y^2) condition and not only just the if clause?

Thanks in advance for the reply!
 
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esmeco said:
Hello!

Homework Statement



Well,I'm having a problem drawing level curves for piecewise functions.
The problem is, how do I know which value the constant k will hold?

Homework Equations



The functions is the following:

f(x,y)=4 if x^2+y^2<=16
sqrt(32-x^2-y^2) if 16<x^2+y^2<=32

The Attempt at a Solution



The solution I've attempted and which I'm not sure it's correct is:
I've drawn a level curve of level 4,because it's within the domain of f(x,y)(which is ]-infinity;32]) and it's the point where the function changes to the other branch.
Does this make sense?

Just another question,to determine the domain of the second "piece" of the function,why do we also use the sqrt(32-x^2-y^2) condition and not only just the if clause?

Thanks in advance for the reply!

I don't know if following would help you.

z = sqrt(32-x^2-y^2) ==> z^2 + x^2+y^2 = (sqrt(32))^2
this is a sphere.

first draw level curves for this,

and then erase all but curves that are between circles with 4 and (sqrt(32))^2
 
What I don't understand is,why do we use the k constant with value 4 specifically?Why couldn't we use other value?
Also,in the second piece of the function why do we equal sqrt(32-x^2-y^2)=4?Does it have anything to do with the fact that 4 is the point where the function switches to the other branch?
 
Level curves are curves of f(x,y, z)= k for severa; different values of k. Use whatever values of k you like.
 
Do the values of k must be within the range of the function?
 

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