How Do You Determine the Direction of an Electric Field?

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Homework Help Overview

The discussion revolves around determining the direction of an electric field associated with a negative charge of -5.0C, given that an electric field of magnitude 2.5N is directed to the left. Participants are exploring how to interpret the relationship between the charge and the electric field, particularly focusing on the directionality of the field.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of vector equations to relate force and electric field, questioning how to determine the direction of the electric field based on the negative charge. There is confusion about the role of a positive test charge and how it interacts with the negative charge in the context of the electric field.

Discussion Status

There is an ongoing exploration of the concepts involved, with some participants suggesting formal methods and definitions related to negative charges. Multiple interpretations of how to approach the problem are being considered, particularly regarding the direction of forces and fields.

Contextual Notes

Participants mention differing instructions from a teacher regarding the use of signs in equations, which adds to the complexity of understanding the problem. There is also a noted confusion about the wording of the question and the typical use of a positive test charge in such scenarios.

Balsam
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Homework Statement


An electric field with a magnitude of 2.5N directed to the left, acts on a negative charge of -5.0C. Determine the electric field in which the charge is located.

Give. FE=2.5N
q=-5.0C

Homework Equations


FE[/B]=qε

The Attempt at a Solution


ε[/B]=2.5N/5.0C=0.5N/C. I don't know how to find the direction. The answer is 0.5N/C,
but I don't know how to get that direction. I guess we have to assume the positive test charge is to the right of q and figure out the direction it would move as a result of FE applied on it by q. That doesn't really make sense though.

Edit: I don't know why the formatting is weird. Also, please help- my exam is tomorrow!​
 
Last edited:
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Use vector equation ##\mathbf F = q \mathbf E##. With ##\mathbf F = -2.5 \hat x## and ##q = -5\hspace{2mm} C##, solve for ##\mathbf E##.
 
blue_leaf77 said:
Use vector equation ##\mathbf F = q \mathbf E##. With ##\mathbf F = -2.5 \hat x## and ##q = -5\hspace{2mm} C##, solve for ##\mathbf E##.
I did, but I don't know how to find the direction
 
You did, then please write out your answer for ##\mathbf E##, note that the bold symbol denotes vector notation so your answer must consist of a number and the unit vector.
 
blue_leaf77 said:
You did, then please write out your answer for ##\mathbf E##, note that the bold symbol denotes vector notation so your answer must consist of a number and the unit vector.
Ok, and how do you find the direction?
 
If you really have calculated ##\mathbf E##, not just ##|\mathbf E|##, then show it in your next comment.
 
blue_leaf77 said:
If you really have calculated ##\mathbf E##, not just ##|\mathbf E|##, then show it in your next comment.

My teacher said you're not supposed to plug in - signs into the equations for fields because it implies direction, so we only use magnitudes
 
I don't know in which manner your teacher wants you to find the direction, but the formal way is to use the vector equation. Alternatively, you can use the definition of negative charge. A negative charge is defined to be the condition such that the field the particle is exposed to exert a force in an opposite direction to that field.
 
blue_leaf77 said:
I don't know in which manner your teacher wants you to find the direction, but the formal way is to use the vector equation. Alternatively, you can use the definition of negative charge. A negative charge is defined to be the condition such that the field the particle is exposed to exert a force in an opposite direction to that field.

I'm confused about the wording of the question. Usually we use a positive test charge along with the given charge. Is the test charge applying the force on q? Then it would be to the right of q since the force is directed to the left. And then q would move to the right as it is attracted by the positive test charge?
 
  • #10
Balsam said:
Then it would be to the right of q since the force is directed to the left.
That's indeed the definition of negative charge when applied to the current problem at hand.
Balsam said:
And then q would move to the right as it is attracted by the positive test charge?
No, the charge will move in the same direction as the force, not the field.
 
  • #11
blue_leaf77 said:
That's indeed the definition of negative charge when applied to the current problem at hand.

No, the charge will move in the same direction as the force, not the field.
But the answer is
 
  • #12
Balsam said:
Then it would be to the right of q since the force is directed to the left
You already arrived at the correct answer there.
 

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