How Do You Determine the Exact Phase Difference in Single Slit Diffraction?

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Homework Statement



See figure attached.

Homework Equations





The Attempt at a Solution



[tex]\Delta L = asin\theta = m \lambda[/tex]

If the waves are in phase, we would expect L to me a integer number of wavelengths, when they are out of phase, L should be an odd number of wavelengths, but when I compute,

[tex]\frac{\Delta L}{\lambda}[/tex]

I get neither an integer nor an odd number. This tells us that the waves must be somewhere inbetween being completely in phase or completely out of phase, but how do I find the exact result?
 

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The problem doesn't say the point on the screen corresponds to a maximum or minimum, so there's no reason to expect the two waves to be out of phase by a multiple of half a wavelength.

The problem is asking you to find the phase difference between the two waves. What causes the waves to arrive with different phases?
 
vela said:
The problem doesn't say the point on the screen corresponds to a maximum or minimum, so there's no reason to expect the two waves to be out of phase by a multiple of half a wavelength.

The problem is asking you to find the phase difference between the two waves. What causes the waves to arrive with different phases?

The path length difference, isn't it?
 
vela said:
Yup, so what you want to do is find the path length difference and translate that into a phase difference.

Okay, well I showed in my first post that I know how to get the path length difference, so how do I make the translation into a phase difference?
 
vela said:
Oh, sorry, I didn't get what you getting at in your first post.

Every time the path length difference increased by wavelength λ, the phase difference increases by 2π.


Ahhhh! That's the key I was missing, so the answer is C correct?