- #1

toesockshoe

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## Homework Statement

I have a question on a practice midterm my professor sent out. I would ideally ask him, but I won't see him until itake my midterm. Instead I am attaching the question and solutions at attachments. THe question of interest is in the attachment "physics question" and the solution from the professor on "physics answer"

The question I have a problem with is number 1b. (part b of the first problem). The part that asks you to draw a phasor diagram and and asks you what the intensity is.

## Homework Equations

look below

## The Attempt at a Solution

They said the total phase difference beta (the angle between the first and last phasor) is 5pi/3. so [tex] \beta = \frac{5\pi}{3} [/tex]

Next they say that because there are 5 phasors, the angle between each phasor is pi/3 (because B/5 is pi/3). I don't think that's right. Suppose you only had 2 phasors... the angle between the 2 phasors ISNT B/2 (or 5pi/6) ...its 5pi/3 because there's only 2 phasors, the angle between them is the same as the angle between the first and last vector. I think the correct formula for the angle between phasor is Beta/(n-1) where n is the number of phasors. Thus I think the angle between each phasor is 5pi/12, which makes drawing them slightly more complicated and finding the intensity though the diagram much more complicated.

If I am wrong, can someone correct me and tell me why?