How do you differenciate Log2(1-2x)

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SUMMARY

The derivative of the function log2(1-2x) is calculated using the chain rule and the derivative of logarithmic functions. The correct derivative is -2/(1-2x)ln(2), which can also be expressed as 2/[(2x - 1) ln(2)]. This confirms the application of the chain rule and the properties of logarithmic differentiation. The discussion clarifies the steps involved in deriving this expression, ensuring a solid understanding of logarithmic derivatives.

PREREQUISITES
  • Understanding of logarithmic differentiation
  • Familiarity with the chain rule in calculus
  • Knowledge of natural logarithms (ln)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of logarithmic functions in calculus
  • Practice more examples of logarithmic differentiation
  • Learn about the application of the chain rule in complex functions
  • Explore the relationship between natural logarithms and logarithms of other bases
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Students studying calculus, particularly those focusing on derivatives of logarithmic functions, as well as educators seeking to clarify concepts in logarithmic differentiation.

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Homework Statement


So its log(base2)(1-2x)


Homework Equations





The Attempt at a Solution


I understand that derivative of log(base:a)x equals 1/xlna. However, using (1-2x) for x and 2 for a I got 1/(1-2x)ln2. Of course, i have to use the chain rule, which turns out to be -2. So my final answer is -2/(1-2x)ln2. However, it seems like that is incorrect. please help me.
 
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Your answer looks fine to me, although it could also be written it as 2/[(2x - 1) ln 2]
 

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