How do you find the area of a region using integrals with respect to x or y?

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SUMMARY

The discussion focuses on determining the area of a region defined by the equations X^2 = y and x - 2y = 3 using integrals. A participant attempted to integrate with respect to x, using bounds from 0 to 9, and calculated an area of 32/3. However, another participant pointed out that the graphs of the provided equations do not intersect, indicating that they do not enclose a region for which an area can be calculated. This highlights the importance of verifying the equations before proceeding with integration.

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Homework Statement


decide whether to integrate with respect to x or y. draw a typical approximating rectangle and label its height and width then find the aread of the region

X^2 = y, x-2y = 3

The Attempt at a Solution


i'm not sure how to find if the questions should be repsect to x or y
i tried doing it with respect to X I did it with integral with upper bound being 9 and lower 0 and i plugged in rad x + (x-3)/2 dx and got 45 -4 and the answer is 32/3
HELP
 
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Did you draw a graph of the region? The graphs of the functions you gave don't intersect, so they don't determine a region, so you're going to have a tough time finding its area.

Have you posted the right equations?
 

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