How do you find the difference in the angle of refraction?

  • Thread starter angiep410
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  • #1
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Homework Statement


Sunlight strikes a piece of crown glass at an angle of incidence of 36.7 degrees. Calculate the difference in the angle of refraction between a orange (610. nm) and a violet (410. nm) ray within the glass. The indices of refraction for the orange and the violet are n = 1.522 and n = 1.538, respectively

Homework Equations



I know that the angle of incidence = the angle of reflection

The Attempt at a Solution



I don't really know how to solve this with the information I'm given. I have no idea where to start. Can someone help me?
 

Answers and Replies

  • #2
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This is REFRACTION you need the relationship between Sini and Sinr
 
  • #3
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This is REFRACTION you need the relationship between Sini and Sinr
so then I'm even more confused. So I have sin(36.7)= ? How do I set it up?
 
  • #4
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I know that the angle of incidence = the angle of reflection



This shows me that you're not quite sure what you're being asked.

In every material, the 'n' value (index of refraction) is a function of wavelength. Each wavelength in the visible range of light is received by our eyes as different colours.
The question is asking you: If a beam of white light (containing all wavelengths) strikes the glass at angle ∅, what will be the difference in the refracted angle between orange and violet.

All you have to do is apply snell's law twice (to each colour), and compare the answers.
 
  • #5
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But I'm given that the wavelength of orange is 610 nm and the indices of refraction is n = 1.522 and the wavelength of violet is 410 nm and the indices of refraction is n = 1.538. So How do I set it up if I'm given all of this information?
 

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