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Circular Motion of amusement park ride

  1. Oct 15, 2008 #1
    1. The problem statement, all variables and given/known data
    An amusement park ride consists of a rotating circular platform 7.81m in diameter from which 10kg seats are suspended at the end of 3.03m massless chains. when the system rotates, the chains make an angle of 26.1 with the vertical. Gravity = 9.8m/s^2. what is the speed of each seat? answer in units of m/s.


    2. Relevant equations
    F=ma
    acceleration centripetal = v^2/r

    3. The attempt at a solution
    Well i drew a free body diagram and the forces of on the y-axis are Tcos26.1=mg. the forces on the x-axis are (Tsin26.1)r/m=V^2
     
  2. jcsd
  3. Oct 15, 2008 #2

    Redbelly98

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    Homework Helper

    Welcome to PF.

    Good. So T = ____ ?

    If you figure out what r is, and use T from the previous equation, you'll have it solved.
     
  4. Oct 16, 2008 #3
    thanks i solved it
     
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