Kinetic Energy After Some Time Has Elapsed

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Homework Help Overview

The discussion revolves around a physics problem involving kinetic energy and the motion of a ball dropped from a height. The original poster attempts to calculate the kinetic energy of the ball after a specific time interval, raising questions about the correct application of gravitational acceleration in their calculations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of velocity and kinetic energy, questioning how to accurately determine kinetic energy after one second of free fall. There are hints regarding the use of gravitational acceleration and its role in the calculations.

Discussion Status

Participants are exploring the implications of gravitational acceleration on the velocity of the ball. Some guidance has been offered regarding the use of known constants, but there is no explicit consensus on the method to find kinetic energy after one second.

Contextual Notes

There is a mention of constraints related to the information available to the original poster and the need to reference standard values for gravitational acceleration.

quido
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A balla of mass 5 kg is dropped from a height of 10 meters. What is the kinetic energy after 1 second has elapsed?First i found the velocity using this equation V^2=2gh = 14m/s

Then I used this equation to find Kinetic Energy KE=1/2mv^2 and got this 490 J.

But i don't know how to find KE after 1 second elapsed. Can anyone help me?
 
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quido said:
But i don't know how to find KE after 1 second elapsed.
Hint: What's the acceleration due to gravity?
 
Doc Al said:
Hint: What's the acceleration due to gravity?

That's the all information I have.
 
quido said:
That's the all information I have.
The acceleration due to gravity is a constant. Check your book. (Hint: It's used in that equation you posted earlier.)
 
oh right. You mean 9.81m/s^2.

I used that to find Velocity? Was it wrong ?
 
quido said:
oh right. You mean 9.81m/s^2.

I used that to find Velocity? Was it wrong ?
Yes, that's what I mean. Now use it to find velocity after 1 second.
 
Oh thanks a lot.
 

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