How do you graph vectors on a graph paper using their magnitude and direction?

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To graph vectors on graph paper, convert their magnitudes from Newtons to centimeters for clarity, as demonstrated with Vector A (1.96N at 20°) and Vector B (1.71N at 65°). After scaling, the vectors were graphed accurately using a protractor and ruler, leading to the resultant Vector C. There was confusion regarding whether to keep Vector C as is or revert to the original scale, with discussions clarifying that the vectors are being added. The angle of Vector C raised questions since it exceeded 90 degrees, despite both original vectors being less than that. A diagram was suggested to clarify the vector addition process and angles.
stolencookie

Homework Statement


Vector A: 1.96N at 20°
Vector B: 1.71N at 65°

Homework Equations

The Attempt at a Solution


I change the Newtons to cm. Vector A: 1.96cm and Vector B: 1.71cm. I multiplied it by 2 so it would look bigger on the graph paper. Vector A: 3.92cm and Vector B:3.42cm. I was able to graph it correctly using my protractor and ruler. I then attached the vectors together to find Vector C: 2.58cm at 95°. Thing is would I keep the Vector C as is or change it back to the original by dividing by 2? I am just confused
 
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Are the vectors being added or subtracted?
stolencookie said:
1.96N at 20°
What does "at 20°" mean? Do you mean 20° clockwise (or maybe anticlockwise) from N?
stolencookie said:
would I keep the Vector C as is or change it back to the original by dividing by 2?
You have mapped 1N to 2cm, right? Use the same mapping to read off the answer in N.
 
haruspex said:
Are the vectors being added or subtracted?

What does "at 20°" mean? Do you mean 20° clockwise (or maybe anticlockwise) from N?

You have mapped 1N to 2cm, right? Use the same mapping to read off the answer in N.

Vectors are being added its clockwise
 
stolencookie said:
Vectors are being added its clockwise
Then I don't understand how you could get an answer with angle greater than 90 degrees when each constituent vector has an angle between 0 and 90.
Can you post a diagram?
 
haruspex said:
Then I don't understand how you could get an answer with angle greater than 90 degrees when each constituent vector has an angle between 0 and 90.
Can you post a diagram?
my bad anticlockwise...
 
stolencookie said:
my bad anticlockwise...
Same response, I do not see how you coukd get that answer.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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