MHB How Do You Integrate Trigonometric Functions with Substitution?

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To integrate the function sin(pi*x)*sqrt(1 + 2*pi*cos(pi*x)^2, the correct substitution is u = cos(pi*x), leading to du = -pi*sin(pi*x)dx. This transforms the integral into a more manageable form. The discussion highlights the need to simplify the expression to sqrt(u^2 - u) but indicates uncertainty on how to proceed from there. Participants emphasize the importance of correctly applying the substitution to facilitate integration. The conversation focuses on clarifying the steps necessary for successful integration using trigonometric identities and substitution techniques.
annie122
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how do i integrate sin(pi*x)*sqrt(1 + pi*2*cos(pi*x)^2)?
i reduced this to sqrt(u^2-u) but i don't know how to go from here
 
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Re: integration

I think what you have written should be interpreted as:

$$\int \sin(\pi x)\sqrt{1+2\pi\cos^2(\pi x)}\,dx$$

Is this correct? And if so, what substitution did you use?
 
Re: integration

Yuuki said:
how do i integrate sin(pi*x)*sqrt(1 + pi*2*cos(pi*x)^2)?
i reduced this to sqrt(u^2-u) but i don't know how to go from here

Substitute \displaystyle \begin{align*} u = \cos{ \left( \pi \, x \right) } \implies du = -\pi\sin{ \left( \pi \, x \right) } \, dx \end{align*} to start with...
 
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