ends
- 9
- 0
(-2e^2t)(sin(4t)) , (-2e^4t)(cos(4t))
(-2e^2t)(cos(4t)) , (2e^4t)(sin(4t))
Please and Thank you!
(-2e^2t)(cos(4t)) , (2e^4t)(sin(4t))
Please and Thank you!
The discussion centers around inverting a specific 2x2 matrix that contains exponential and trigonometric functions. Participants explore the application of the inversion formula and seek clarification on handling complex expressions within the matrix.
Participants generally agree on the use of the matrix inversion formula, but there is uncertainty regarding its application to the specific complex terms in the matrix. The discussion remains unresolved regarding the complete inversion process.
Participants do not fully resolve the mathematical steps involved in applying the inversion formula to the complex matrix, and there are missing details about the assumptions made in the calculations.
MarkFL said:Can you show us what you have tried? Our helpers will be better able to provide you with relevant help if they can see where you are stuck and/or where you may be making mistakes.
ends said:So since it's a 2x2 matrix, it's easier to use the equation A(INVERSE) = (1/ad-bc)(d , -b
-c , a)
I get stuck here, I don't really know how to apply this formula when it's in a more complex form like this.
Jameson said:Hi ends!
I don't see why that formula wouldn't work here. Try calculating $ad$ and $bc$ first. What is $(-2e^{2t}\sin(4t))*(2e^{4t}\sin(4t))$ for example?
ends said:Thank you, but can you equate this one for me so I have a general idea of how to multiply these two large terms? I'm not entirely sure how to go about it, and since it's my last chance to submit it online, I don't want to mess it up.