How Do You Model the Changing Concentration of Nitric Acid in a Tank?

Tapias5000
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Summary:: A nitric acid solution enters at a constant rate of 6 liters / minute into a large tank that originally contained 200 liters of a 0.5% nitric acid solution. The solution inside the tank is kept well stirred and leaves the tank at a rate of 8 liters / minute. If the solution entering the tank has 20% nitric acid, determine the volume of nitric acid in the tank after t minutes. When will the percentage of nitric acid in the tank reach 10%?

A nitric acid solution enters at a constant rate of 6 liters / minute into a large tank that originally contained 200 liters of a 0.5% nitric acid solution. The solution inside the tank is kept well stirred and leaves the tank at a rate of 8 liters / minute. If the solution entering the tank has 20% nitric acid, determine the volume of nitric acid in the tank after t minutes. When will the percentage of nitric acid in the tank reach 10%?

How do I solve the 10% question I got this far.
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I'd like to see your derivation of the equations. Here is my derivation: I think you are supposed to assume the percentage nitric acid is the volume percentage and that the solution overall density doesn't change. So, based on this, the volume of fluid in the tank is V = 200-2t, the amount of nitric acid in the tank at any time is FV, the rate of nitric acid entering is (6)(0.2), and the rate of nitric acid leaving at any time is 8F, where F is the fraction nitric acid in the tank at any time. So my nitric acid balance o the tank is $$\frac{d(VF)}{dt}=(6)(0.2)-8F$$ The initial condition is F = 0.005
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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