How Do You Model Water Draining from a Spherical Tank Over Time?

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Discussion Overview

The discussion revolves around modeling the drainage of water from a spherical tank over time, focusing on the relationship between the height of the water and time. Participants explore fluid mechanics principles, particularly the application of Bernoulli's equation and the dynamics of fluid flow through an orifice.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant describes the problem of a spherical tank draining water through a small hole and proposes using Bernoulli's equation to derive the velocity of the water leaving the tank.
  • Another participant suggests that the volume of water should be expressed in terms of the height to facilitate the calculation of the rate of change of volume with respect to height.
  • A different participant presents a similar problem involving a tank with a hole at the bottom, noting the influence of atmospheric pressure on the water surface and questioning how to formulate this in an equation.
  • One response outlines a general approach to the problem, emphasizing the need to set up a differential equation based on the volume flow rate out of the tank and integrating to find the height as a function of time.

Areas of Agreement / Disagreement

Participants generally agree on the need to apply fluid mechanics principles to model the drainage process, but there are varying approaches and assumptions regarding the equations and conditions involved. The discussion remains unresolved with multiple perspectives on how to proceed.

Contextual Notes

Participants express uncertainty about specific mathematical steps and how to incorporate various factors such as pressure and height into their equations. There is also a lack of consensus on the exact formulation needed to model the drainage accurately.

bige1027
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Fluid Mechanics - Draining sphere - I need Help!

I just found this forum and it seems like a wealth of knowledge; wish I had found it sooner. Looking for some help and if anyone can, it will be appreciated more than you'll ever know.

Here's the problem:

A spherical tank of diameter D is filled with water. It has a small vent at the top to allow for atmospheric pressure within the tank. The water drains from a small drain hole at the bottom (dia=1 inch). The flow is quasi steady and inviscid. Find a function for the height of the water w.r.t. time, h(t), where 'h' is the height of the water measured from the bottom of the sphere.
Use the function to determine the water depth for D=1, 10, and 50 ft.

This is what I have:
It's a "free jet" probelm, so the water draining at the bottom leaves with a velocity of V=sqrt(2*g*h) - derived from the Bernoulli eq. with points at the top of bottom of the sphere.

The flowrate out is Q=AV=[(pi/4)*(1/12)^2]*[sqrt(2*g*h)]

Volume sphere = 4/3 *pi*R3

Here I've been stuck for a long time. Does anyone have any ideas where to go from here?
 
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So far, you're on track.

What you need to do next is be able to write down the volume of water in terms of the height.

Look at eqn (6) here and make the appropriate changes (if necessary).

Then you find the rate of chage of volume in terms of the rate of change of height and equate that to the outflow.
 
fluid mech-draining tank

i kind of have the same problem, only i am dealing with a tank, with a hole at the bottom and the water surface having a pressure of 1 atm. the question is, how long will it take for the water to drain? i have assumed that the velocity of water coming out of the small hole is>>> than the velocity of the water surface so that the latter is approx=0.
i know the rate of water drainage changes according to the pressure and height of the water level inside. i just don't know hot po put this concept in equation. any help would really be appreciated!
 
What you need is:

Accumulation = in - out + reaction

Is there accumulation? Yes.
Is there in? No.
Is there out? Yes.
Is there reaction? No.

You should get something like: dV/dt = 0 - A.v(t)
Just calculate V(h) and you know v(t) = sqrt(2gh(t))
So you have a diff equation with variable h(t), you integrate and you have h(t).

Then you fill in h = 0 and there it is!
 
Last edited:

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