How do you Simplify 4^(7/3) - 12^(4/3)? Please Step by Step

  • Thread starter Thread starter mgmarygg
  • Start date Start date
  • Tags Tags
    Simplify
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
mgmarygg
Messages
1
Reaction score
0

Homework Statement


(Square Root Exponents) 4(7/3) - 12(4/3)

For this problem The answer is 4x^2 - 12x but i tried i could not seem to obtain the same answer, could you please explain on how to do this step by step so I know do the rest of other problems


Homework Equations





The Attempt at a Solution



stuck :( 3√4x)7 - (3√12x)4
= (3√47x7) - (3√124x4)...
 
Last edited:
Physics news on Phys.org
mgmarygg said:

Homework Statement


(Square Root Exponents) 4(7/3) - 12(4/3)

For this problem The answer is 4x^2 - 12x but i tried i could not seem to obtain the same answer, could you please explain on how to do this step by step so I know do the rest of other problems
What exactly is the problem? From the title it looks like you need to simplify 47/3 - 124/3, but this has absolutely nothing to do with 4x2 - 12x.

And what do "square root exponents" mean?
mgmarygg said:

Homework Equations





The Attempt at a Solution



stuck :( 3√4x)7 - (3√12x)4
= (3√47x7) - (3√124x4)...
 
I think the correct equation is:

4 x ^ (7/3) - 12 x ^ (4/3)

Remember that x ^ (7/3) = x^2 * x ^ (1/3)

and that x ^ (4/3) = x * x^(1/3)
 
Last edited by a moderator:
Assuming the above expression is correct, don't forget that you can factor out exponents. Don't let the fact that they're fractions distract you.