How Do You Solve a Sequence Summation Problem with Variable k?

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SUMMARY

The sequence defined by Un = 5n + 20 requires solving for N in the equation where the sum of the first N terms equals the sum of the first kN natural numbers. The correct formulation leads to the equation k^2N^2 + kN = 50N + 5N^2 - 5N. The solution simplifies to N = (45 - k) / (k^2 - 5). Key steps include substituting kN into the natural number sum formula and correctly grouping terms after dividing by N.

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Homework Statement



A sequence of terms U1, U2, U3, ... is defined by Un = 5n + 20

If the sum of the first N terms of the sequence defined above equals the sum of the first kN natural numbers, show that:

N = 45 - k / k^2 - 5

Homework Equations



Sum of first N natural numbers = N(N+1)/2

Sum of sequence = N(50+(N-1)5)/2 (knowing that a=25, d=5)

The Attempt at a Solution



I put the substituted kN into N in the equation N(N+1)/2 to give me kN(kN+1)/2.

I then made kN(kN+1)/2 = N(50+(N-1)5)/2 and solved from there which eventually got me to:

k^2N^2 + kN = 50N + 5N^2 -5

(I then divided both sides by N as N is always positive)

N = 45 +5N -k / k^2

...the +5N makes it wrong. I don't know where I've gone wrong, any help would be appreciated.
 
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Your last expression is right, the only thing you need to do is solve for N.
 
david18 said:

Homework Statement



k^2N^2 + kN = 50N + 5N^2 -5
This one should be k^2N^2 + kN = 50N + 5N^2 -5N, but I suppose this was an inconsequential typo.

(I then divided both sides by N as N is always positive)

N = 45 +5N -k / k^2
Dividing by N is OK, but this is not the result. Just divide the above with N (all the terms contain N so this is easy), and then group terms with and without N.
 

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