How Do You Solve \(\dot y(x) - 2y(x) = y^2(x)-3\) in Differential Equations?

[ENgez]

Homework Statement

I need to find a general function y(x) such that:
$$\dot y(x) - 2y(x) = y^2(x)-3$$

Homework Equations

The Attempt at a Solution

I tried dividing the equation by $$y^2-3$$ and turn it into a Bernoulli differential equation, but that didn't work. The equation seems relatively simple yet i can't recall any method to solve it. Please help.

 

[Mark44]

It's separable. dy/dx = y² + 2y - 3 ==> dy/(y² + 2y - 3) = dx

 

[ENgez]

How could i not see that! i solved it, tnx a lot. :)