How Do You Solve Logarithms with Square Roots?

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  • Thread starter Thread starter Antisubs12
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    Logarithms
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Discussion Overview

The discussion revolves around solving logarithmic expressions that involve square roots, specifically focusing on the expression loge[square root of e]. Participants explore different methods and properties of logarithms to approach the problem.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to solve logarithms involving square roots, specifically asking about loge[square root of e].
  • Another participant introduces a property of logarithms, suggesting that \log_{a}x^y can be rewritten in a different form.
  • A third participant provides a step-by-step breakdown of the expression \ln\sqrt{e}, demonstrating the use of logarithmic rules to simplify it to \frac{1}{2}.
  • One participant asks how to express the square root of e in exponential form and suggests considering logarithmic laws to simplify the problem further.
  • A later reply acknowledges the helpfulness of expressing square roots in exponential form and indicates that the participant feels capable of proceeding with the problem.

Areas of Agreement / Disagreement

Participants generally agree on the usefulness of logarithmic properties in solving the problem, but there is no explicit consensus on a single method or solution approach.

Contextual Notes

Some assumptions about the properties of logarithms and their application to square roots are present, but these are not fully explored or resolved in the discussion.

Who May Find This Useful

Students learning about logarithms and their properties, particularly those encountering logarithmic expressions involving square roots for the first time.

Antisubs12
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I've been working on logarithms in my calculus class and I came acrossed one with a square root. Since I am new to these types of problems I'm not sure how to work with this yet.

How would I solve something such as loge[square root of e]
 
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Welcome to PF, Antisubs12.

Do you know another (equivalent) way to write

\log_{a}x^y = ?
 
Well, \ln\sqrt{e}=\ln e^{1/2}=\frac{1}{2}\ln{e}=\frac{1}{2}. Where the second equality comes from the rule ln(a)^b=b ln(a)
 
how would you write square root of e in expediential form? After you do that ask your self what law of logs will help you make the problem more workable.
 
ah thanks, i had forgotten there was a way to write square roots in exponential form. I can handle things from here. Thanks again.
 

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