How Do You Solve Projectile Motion Problems Involving Angles and Heights?

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SUMMARY

The discussion focuses on solving a projectile motion problem involving an object projected at a velocity of 100 m/s from a height of 150 m at an angle of 30 degrees. The key calculations include determining the time of flight, horizontal distance from the tower, and the final velocity upon impact. The equations utilized are kinematic equations such as x = ut + 0.5at² and v² = u² + 2ax, with specific emphasis on separating the vertical and horizontal components of motion. The solution approach confirms the use of trigonometric functions to resolve the initial velocity into its components.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of trigonometry for resolving vector components
  • Familiarity with projectile motion concepts
  • Ability to apply free fall principles in vertical motion
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  • Study the derivation of projectile motion equations
  • Learn how to apply the conservation of energy in projectile motion
  • Explore advanced projectile motion problems involving air resistance
  • Investigate the impact of varying launch angles on projectile range
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TheKovac
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Homework Statement


A object is projected with a velocity of 100 m/s at an elevations 30 degrees from a tower 150m high.

a) Time of flight
b) The horizontal distance from the tower at which the stone strikes that ground.
c) The magnitude and the direction of the velocity of the stone striking the ground.

Homework Equations


x=ut+0.5at^2
Trigonometry
v^2 = u^2 + 2ax

The Attempt at a Solution



a)

=>v=u+at
50.2=100 -10t
t1= 5.02s
t2 = 5.02s
t3=?

Am I on the right track at all?
 

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TheKovac said:

Homework Statement


A object is projected with a velocity of 100 m/s at an elevations 30 degrees from a tower 150m high.

a) Time of flight
b) The horizontal distance from the tower at which the stone strikes that ground.
c) The magnitude and the direction of the velocity of the stone striking the ground.

Homework Equations


x=ut+0.5at^2
Trigonometry
v^2 = u^2 + 2ax

The Attempt at a Solution



a)

=>v=u+at
50.2=100 -10t
t1= 5.02s
t2 = 5.02s
t3=?

Am I on the right track at all?
what are these t1 t2 and t3 ?
If you have the book PHYSICS by Resnic and Haliday please look in it for the solution.
bye
 
You have some help https://www.physicsforums.com/showthread.php?t=227924".

For the (a) part you have vertical shot (y component of the velocity) and then free fall from the height of 150 m at initial velocity of v_{y}=v_{0}sin\alpha.

For the (b) part you need the x component. You have the time from the (a) part, so it's pretty easy.

(c) part is also simple. You need the net velocity (trigonometry). X component doesn't change but the y component is increased by gravity.
 
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