How Do You Solve the Schrodinger Equation with Spherical Coordinates?

Click For Summary

Homework Help Overview

The discussion revolves around solving the Schrödinger equation using spherical coordinates, with participants exploring the transformation of variables and expressions involved in the problem.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the origin of the expression x² - y² in the context of spherical coordinates and consider various substitutions and transformations. There is uncertainty about the correctness of their approaches and simplifications.

Discussion Status

Some participants have offered tips on manipulating expressions involving trigonometric identities and complex exponentials. There appears to be a progression in understanding, with attempts to verify the correctness of the derived expressions.

Contextual Notes

Participants express uncertainty about their initial steps and the simplification process, indicating a lack of confidence in their understanding of the problem setup and transformations involved.

KingBigness
Messages
94
Reaction score
0

Homework Statement



See attached photo


The Attempt at a Solution



So I have no idea if I have even started this problem correctly so any help would be nice.

My working is set out in one of the pictures.

Any help would be appreciated I really am not quite sure what to do. Can't figure out where the x^2-y^2 comes from.

Thank you!
 

Attachments

  • Screen shot 2011-08-23 at 11.41.26 AM.png
    Screen shot 2011-08-23 at 11.41.26 AM.png
    13.6 KB · Views: 476
  • Screen shot 2011-08-23 at 12.02.41 PM.png
    Screen shot 2011-08-23 at 12.02.41 PM.png
    9.9 KB · Views: 478
Physics news on Phys.org
Hi KingBigness! :wink:
KingBigness said:
Can't figure out where the x^2-y^2 comes from.

I'm guessing really, since this isn't my field :redface:, but if you replace r2sin2θcos2φ by r2sin2θ(cos2φ - sin2φ), that looks like x2 - y2 :smile:
 
Leave the r2 alone for now and use the fact that[tex]\cos \theta = \frac{e^{i\theta} + e^{-i\theta}}{2}[/tex]to get rid of the complex exponentials.
 
Thank you both for that, I shall try that and let you know how I go
 
Ok I tried that and out came the x^2-y^2

Thank you for that tip.

This is the answer I have ended up with can you let me know if it is correct or if I need to simplify it more? not really sure when to stop =\
 

Attachments

  • photo.jpg
    photo.jpg
    23.3 KB · Views: 407
I lied above...I brought the sin theta squared in before I converted which got rid of the sin theta squared in the final answer.

Is this now correct?
 
Yes, that's right, because in spherical coordinates x = r sin θ cos φ and y = r sin θ sin φ.
 
vela said:
Yes, that's right, because in spherical coordinates x = r sin θ cos φ and y = r sin θ sin φ.

Sweet finally got this question complete!

Thank you. Will double check all my algebra later to make sure I haven't done a silly mistake.

Thanks again for your help
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
29
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K