How Do You Solve the Sum of 3^k/k! from 0 to Infinity?

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Homework Help Overview

The problem involves evaluating the sum of the series 3^k/k! from 0 to infinity, which falls under the topic of infinite series and potentially relates to exponential functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find a starting point for the evaluation and considers using the geometric series formula. Other participants suggest exploring the function f(x) defined by the series and its derivative, as well as recognizing connections to Taylor's series.

Discussion Status

Participants are exploring various approaches to understand the series, with some suggesting the use of derivatives and Taylor's series. There is a recognition of potential connections to the binomial formula, although no consensus has been reached on the best method to proceed.

Contextual Notes

There is mention of a hint regarding the binomial formula that may influence the interpretation of the problem, but its relevance is not fully established in the discussion.

Office_Shredder
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I've been staring at this stupid problem for a while, and finally gave up and came here. The question is to evaluate the sum of 3k/k! from 0 to infinity. Basically, I'm looking for a starting spot, since I have none. The closest thing to a strategy I've come up with is plugging it into the geometric series formula with r=3/k, but that didn't work so well :rolleyes:
 
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Let

[tex]f(x) = \sum_{k=0}^{\infty}\frac{x^k}{k!}[/tex]

What is f'(x)? In particular, how does f'(x) relate to f(x)? What other functions relate to their derivatives in that way? If you know some stuff about differential equations, you'll know that only one type of function relates to its derivative in that way. So you can figure out what type of function f(x) is, and by plugging in x=0, you get an initial value problem which allows you to find what function f(x) is specifically. Once you know what f is, your final answer is f(3).
 
Actually, if you have worked with Taylor's series, you ought to be able to look at that series and recognize it immediately. If not, AKG's suggestion is excellent: take the derivative, term by term, then slap your forehead and say "oh, of course!".
 
After mentioning taylor's series, it's pretty obvious... unfortunately, for some obnoxious reason right before the question there was a hint about the binomial formula, so I got the impression it was supposed to be involved with that somehow. (especially since the three questions after it were).

Thanks
 
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