How Do You Solve This Inverse Laplace Transform Equation?

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SUMMARY

The discussion focuses on solving the inverse Laplace transform of the equation \(\frac{3s+9}{(s+3)^2+7}\). The user initially attempted to apply the partial fractions method but encountered difficulties with factorization, specifically with the quadratic expression \(s^2 + 6s + 16\), which does not factor into linear components with real coefficients. The correct approach involves recognizing the translation represented by \(s + 3\) and utilizing the known inverse Laplace transform of \(\frac{3s}{s^2 + 7}\). The thread concludes with a clarification that partial fractions are not applicable in this scenario.

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  • Understanding of inverse Laplace transforms
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  • Knowledge of quadratic equations and their factorization
  • Basic concepts of Laplace transforms in engineering and mathematics
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Students in engineering and mathematics, particularly those studying control systems or differential equations, will benefit from this discussion. It is also valuable for anyone seeking to deepen their understanding of Laplace transforms and their applications.

casper12
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Homework Statement


Determine the inverse Laplace transform

Homework Equations


3s+9.
(s+3)^2+7

The Attempt at a Solution


[/B]
Hi iam new to the forum and still unsure how to make the equations the correct format so hope you can understand what I have typed.

I have Tried to Convert the original equation into the equation below to try and use the partial fractions method but getting nowhere.

3s+9.
s^2+6s+16 I'm Not sure if Iam making the question more difficult, can't seem to put the division side of the equestion into brackets.

Attempt was (s-2)(s+8) but that results in s^2+6s-16 resulting in an incorrect sign. Can't seem to change the signs to make it correct.

Not sure if partial fractions method is the best method or if I'm making it more difficult than it is.

Any advice much appreciated.
 
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casper12 said:

Homework Statement


Determine the inverse Laplace transform

Homework Equations


3s+9.
(s+3)^2+7

The Attempt at a Solution


[/B]
Hi iam new to the forum and still unsure how to make the equations the correct format so hope you can understand what I have typed.

I have Tried to Convert the original equation into the equation below to try and use the partial fractions method but getting nowhere.

3s+9.
s^2+6s+16I'm Not sure if Iam making the question more difficult, can't seem to put the division side of the equestion into brackets.

Attempt was (s-2)(s+8) but that results in s^2+6s-16 resulting in an incorrect sign. Can't seem to change the signs to make it correct.

Not sure if partial fractions method is the best method or if I'm making it more difficult than it is.

Any advice much appreciated.
Write your expression as ##\frac{3(s + 3)}{(s + 3)^2 + 7}##
The s + 3 expressions represent a translation to the left of ##\frac{3s}{s^2 + 7}##. If you can recognize what the inverse Laplace Transform of this expression is, and take care of the translation represented by s + 3, you should be able to answer your question.

Regarding using partial fractions, your factorization of (s - 2)(s + 8) is obviously wrong, as this doesn't give you s2 + 6s + 16. This quadratic doesn't factor into linear factors with real coefficients, so that technique is not useful here.
 
Thread closed. The original thread is in the Engineering & CS Homework section.
 

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