How Do You Take the Covariant Derivative of a Tensor Twice?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 4K views
Mr-R
Messages
123
Reaction score
23
Doing some problems in D'INVERNO GR textbook and I am stuck on taking the covariant derivation of a tensor twice. Please see the attached picture and please do inform me if something is not clear :smile:
 
Attachments
  • 1404967929479.jpg
    1404967929479.jpg
    26.4 KB · Views: 499
Physics news on Phys.org
Hello.
Where do e comes from??

Take ##A^i=B^i_jC^j##.
j is a dummy index, there is a summation over j.
i can be 1, 2 or 3. This equation tells that the equality is true for all three values of i.
##A^k=B^k_jC^j## is exactly the same as ##A^i=B^i_jC^j##, you must not keep track of indices from one equation to another.
 
Heya bloby,

For e, I just chose a new tensor to represent the covariant derivative of the original tensor. Then what should I have named it? T[itex]^{a}_{b}[/itex] ?

Thanks
 
Rather ##T^a_d## the same indices than LHS. The indices are related to basis element. They must be consistent within an equation, like ##v^i=\frac{dx^i}{dt}##, not ##v^i=\frac{dx^j}{dt}##. The 3rd and 4th line of the thumbnail are the same(after corrections) with renamed indices .
 
bloby said:
Rather ##T^a_d## the same indices than LHS. The indices are related to basis element. They must be consistent within an equation, like ##v^i=\frac{dx^i}{dt}##, not ##v^i=\frac{dx^j}{dt}##. The 3rd and 4th line of the thumbnail are the same(after corrections) with renamed indices .

Much Appreciated bloby :smile:

Thanks