How Do You Use a Z-Score Table for Probability Calculations?

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Homework Help Overview

The discussion revolves around calculating probabilities using a Z-score table for a normal random variable with a specified mean and standard deviation. Participants are exploring how to interpret Z-scores and the corresponding probabilities for values greater than or less than certain thresholds.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of Z-scores and the interpretation of values obtained from the Z-table. There is confusion regarding when to retain the probability value from the Z-table versus when to subtract it from 1. Some participants express uncertainty about the transformation of inequalities and the implications of Z-scores being positive or negative.

Discussion Status

The discussion is ongoing, with participants providing insights and suggestions for visualizing the problem through sketches of the normal distribution. There is an emphasis on understanding the relationship between Z-scores and the areas under the curve, although no consensus has been reached on the specific calculations.

Contextual Notes

Participants are working within the constraints of homework guidelines, which may limit the extent of assistance they can provide to one another. The original poster and others are grappling with the correct application of Z-scores in probability calculations.

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Homework Statement


Let X be a normal random variable with mean 80 and standard deviation 5. What is the probability X is greater than 87? Less than 74?
I understand how to compute the z score but I'm confused as to when I have to keep the number from the z-table or subtract 1

Homework Equations


z= x-μ /σ

The Attempt at a Solution


z = 1.4
P (z > 87 ) = ??
I found the z score to be 0.9192 but do I keep this value as my answer or do I do 1 - 0.9192z=-1.2
P (z < 74)= ??
again, I found z score to be .1151
So I keep this value or 1 - 0.1151 and why?
Thank you
 
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tsukuba said:

Homework Statement


Let X be a normal random variable with mean 80 and standard deviation 5. What is the probability X is greater than 87? Less than 74?
I understand how to compute the z score but I'm confused as to when I have to keep the number from the z-table or subtract 1

Homework Equations


z= x-μ /σ
You need parentheses when you write things like this. It should be z = (x - μ )/σ. As you wrote it, it would be interpreted as z = x - (μ /σ).
tsukuba said:

The Attempt at a Solution


z = 1.4
P (z > 87 ) = ??
No, the above should be P(X > 87). You get the z-score by transforming the inequality, like so:
P(X > 87) = ##P(\frac{X - 80}{5} > \frac{87 - 80}{5}) = P(z > \frac{7}{5}) = P(z > 1.4)##

tsukuba said:
I found the z score to be 0.9192 but do I keep this value as my answer or do I do 1 - 0.9192
No, the z-score is 1.4, and the probability associated with it is 0.9192. This probability is the area under the standard normal curve (the "bell curve") between -∞ and 1.4.

It's very helpful to draw a quick sketch of the bell curve, including your z-score and the probability value you get from the table. With a sketch you can easily see which area under the curve you're interested in.
tsukuba said:
z=-1.2
P (z < 74)= ??
again, I found z score to be .1151
So I keep this value or 1 - 0.1151 and why?
Thank you
 
Last edited:
tsukuba said:

Homework Statement


Let X be a normal random variable with mean 80 and standard deviation 5. What is the probability X is greater than 87? Less than 74?
I understand how to compute the z score but I'm confused as to when I have to keep the number from the z-table or subtract 1

Homework Equations


z= x-μ /σ

The Attempt at a Solution


z = 1.4
P (z > 87 ) = ??
I found the z score to be 0.9192 but do I keep this value as my answer or do I do 1 - 0.9192z=-1.2
P (z < 74)= ??
again, I found z score to be .1151
So I keep this value or 1 - 0.1151 and why?
Thank you

As Mark44 has said: draw a picture---even a very crude (but symmetric) picture will do. For any z, P(Z<z) is the area to the left of the point z under the graph of the unit normal density, so if z < 0, P(Z < z) < P(Z < 0) = 1/2, while P(Z > z) > P(Z > 0) = 1/2. So, if you are given a probability value P(Z < z ) < 1/2 or P(Z > z) > 1/2, you know that z < 0. If you are given the opposites of these, you know that z > 0.
 
Thank you both
Did well on my exam
 

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