Normal and binomial distribution: using Z-scores to find answer

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SUMMARY

The discussion centers on calculating the maximum price a fruit shop owner is willing to pay for bananas using normal distribution and Z-scores. The mean price is $1.35/kg with a standard deviation of $0.18. The owner maintains stock 8% of the time, leading to a Z-score of approximately 0.201. By applying the Z-score formula Z=(X-μ)/σ, the maximum price the owner is willing to pay is determined to be $1.31/kg.

PREREQUISITES
  • Understanding of normal distribution and Z-scores
  • Familiarity with statistical concepts such as mean and standard deviation
  • Ability to use Z-score tables for probability calculations
  • Basic algebra for rearranging formulas
NEXT STEPS
  • Study the application of Z-scores in different statistical contexts
  • Learn about the implications of standard deviation in pricing strategies
  • Explore advanced topics in normal distribution, including confidence intervals
  • Investigate the use of statistical software for calculating probabilities
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Statisticians, data analysts, business owners, and anyone involved in pricing strategy and inventory management will benefit from this discussion.

jackscholar
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The prices for bananes that a fruit shop would have to pay to keep them in stock have a mean of $1.35/kg and a standard deviation of 18 cents. The owner will not pay more than a certain price, but manages to keep stock 8% of the time. What is the maximum price the ownwer will pay?

I found 0.08 on a Z-score table and it was approximately Z=0.201. This is a negative number because it is less than the mean (or so i figured). I used the formula Z=(X-μ)/σ and re-arranged to get (-0.201*0.18)+1.35= price he is willing to pay. This then gave $1.31.
 
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"...but manages to keep stock 8% of the time"

means the probability the owner will have stock left at the end of the day is 8%, or 0.08. Stated another way, there is only an 8% chance that the demand for his product will be greater than what he has on hand. This means the Z-score you seek is the one that cuts off the right-hand 8% of the distribution, so should not be a negative value. Your basic idea for attacking the problem seems correct, except for this item.
 

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