How Do You Use the Maclaurin Series to Evaluate the Integral of sin(3x^2)?

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SUMMARY

The discussion focuses on using the Maclaurin series to evaluate the integral of sin(3x^2) from 0 to 0.72. Participants confirm that the Maclaurin series for sin(x) can be applied, leading to the series representation of sin(3x^2) as an infinite series. The first two terms of the series are utilized to estimate the integral's value, resulting in the expression ((-1)^n(3^(2n+1)0.72^(4n+3))/((2n+1)!(4n+3)). This approach provides a method for approximating the integral using series expansion.

PREREQUISITES
  • Understanding of Maclaurin series and Taylor series expansions
  • Familiarity with the integral calculus concepts
  • Knowledge of factorial notation and its application in series
  • Basic proficiency in evaluating limits and convergence of series
NEXT STEPS
  • Study the convergence criteria for Maclaurin series
  • Learn how to derive Taylor series for other trigonometric functions
  • Explore numerical integration techniques for approximating definite integrals
  • Investigate the application of series expansions in solving differential equations
USEFUL FOR

Students in calculus, mathematicians interested in series expansions, and educators teaching integral calculus concepts.

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Homework Statement



Assume that sin(x) equals its Maclaurin series for all x.
Use the Maclaurin series for sin(3 x^2) to evaluate the integral
int_0^{0.72} sin(3 x^2) dx.
Your answer will be an infinite series. Use the first two terms to estimate its value.

Homework Equations


The Attempt at a Solution



I got

((-1)^n(3^(2n+1)0.72^(4n+3))/((2n+1)!(4n+3))
 
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What do you get for your Maclaurin series for sin(3x^2)?
 

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