How do you work out the volume and concentration when moles are given?

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SUMMARY

This discussion focuses on calculating volume and concentration from given moles in chemistry, specifically using sodium (Na) and sodium hydroxide (NaOH) as examples. The method involves applying stoichiometry to determine the moles of hydrogen gas (H2) produced from the moles of sodium. The volume of gas can be calculated by multiplying the moles of H2 by 24 dm³, which is the molar volume at standard conditions. Additionally, the concentration of NaOH can be derived using the volume provided and the moles of Na reacted.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Knowledge of molar volume at standard conditions (24 dm³)
  • Familiarity with calculating concentration (mol/dm³)
  • Basic understanding of balanced chemical equations
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  • Study stoichiometric calculations in chemical reactions
  • Learn how to calculate molar volume and its applications
  • Research methods for determining concentration from moles and volume
  • Explore balanced equations involving sodium and hydrogen reactions
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Chemistry students, educators, and anyone involved in laboratory work requiring calculations of volume and concentration based on moles.

Soldat99
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Hi everyone.
I was doing a past paper. I got some of the question wrong about finding out Volumes and Concentrations

Could you please Help me with these Question.

I have enclosed the question sheet that has all the work done on it.

If you can't see image properly then use this link

http://img715.imageshack.us/img715/2527/examhelp.jpg

P.s the answer on the sheet are wrong. Therefore I have attached another .jpg pic

Thank you very much for helping.
 

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Since you have the balanced equation and the number of mols of Na, you can find the number of mols of H2 by stoichiometry. Then multiply that by 24dm3.

eta: Use that same basic method to determine the NaOH concentration. You have V given to you.
 
you haven't reacted 1 mole of Na to produce 1 mole of H2. You have reacted 0.05 moles
 

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