How Does a Boat's Position Change with Wind and Currents?

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SUMMARY

The discussion focuses on calculating the displacement of a sailboat propelled westerly at 4 m/s while affected by a northeast current of 2 m/s over a duration of 10 minutes. To determine the boat's total velocity, participants emphasize the necessity of breaking the current's velocity into its x and y components using trigonometric functions. The x-component is calculated as -4 m/s, while the current's components are derived as approximately 1.41 m/s in both the x and y directions. The final displacement can then be computed using the total velocity over the specified time.

PREREQUISITES
  • Understanding of vector components and their addition
  • Knowledge of trigonometric functions for angle resolution
  • Familiarity with the Pythagorean Theorem
  • Basic principles of physics related to motion and velocity
NEXT STEPS
  • Learn how to resolve vectors into components using trigonometric functions
  • Study the application of the Pythagorean Theorem in physics problems
  • Explore the concept of relative velocity in fluid dynamics
  • Practice problems involving displacement and velocity in two dimensions
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nakidhoboe
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Thanks for the help, sorry I am not really good with Physics and i could use some help please.
Homework Statement
A sailboat is being propelled westerly by the wind at a speed of 4m/s. If the current is flowing at 2m/s to the northeast, where will the boat be in 10minutes with respect to its starting position?
 
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The hardest part of this problem is determining the total velocity. Since the boat is traveling in a single direction, no extra work is needed. However to add the current velocity you must first break it into components (which can be done using the Pythagorean Theorem). Once you find the total velocity, you can use it to find the displacement.

From the information you gave, I'm having a hard time determining exactly what you are having difficulty with. If this doesn't help you get the answer, post back with as much of the problem as you can complete, and I can help you further.
 
Break into components? by doing 4^4 + 2^2= 20 then 20^1/2 = 4.47?
 
Alright, I see where you are having troubles now.

Vectors are not like standard numbers that you have been dealing with up until now. They have both a value, and a direction. Therefore, in order to add them, you have to take both into consideration.

First, you need to set up a coordinate system. For this problem it is simple. We can simply call east-west the x-direction and we can call north-south the y-direction.

Now comes the difference between vectors and non-vectors. Different directions cannot simply be added together. You have to do a procedure to separate the directions, which is called breaking the vector into its components.

The first number is 4 m/s west. Since our east-west is on the x-axis, this vector only has one component: -4 m/s on the x-axis (the x-direction is also called the i direction, therefore it can also be written as -4i).

However, the second number is partially in the x-axis and partially on the y-direction. Therefore for this one, we must break it into components in order to add it. Northwest means the vector is at a 45 degree angle between the x-direction and y-direction. If you draw this vector out, it will be much easier to see. In order to find the x and y directions, you will have to use trig functions with the angle and the 2 m/s hypotenuse. You should get (1.41i + 1.41j) for the components. (With j being the y-direction)

When you add these numbers, remember that only the same direction can be added together.

Try to come up with these numbers, and if you need additional help, please don't hesitate to post.
 

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