How Does a Fluctuating Hamiltonian Affect the Expectation Value of Sx?

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SUMMARY

The discussion centers on the effect of a fluctuating Hamiltonian, specifically H = δSz, on the expectation value of Sx in quantum mechanics. Participants confirm that starting with =½ leads to the result = ½, where the average is taken over all values of δ. The method suggested involves using the time-evolution operator to compute , although some participants note that obtaining the eigenfunctions of Sz and projecting Sx onto them may simplify the process. The expectation value can be computed using the relation x^H*Sx*x, where x is the time-evolved state vector.

PREREQUISITES
  • Understanding of quantum mechanics, specifically Hamiltonians and expectation values
  • Familiarity with the concepts of time evolution in quantum systems
  • Knowledge of eigenvalues and eigenvectors in the context of quantum operators
  • Basic proficiency in linear algebra, particularly with matrices and vectors
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  • Study the derivation of expectation values in quantum mechanics using time-evolution operators
  • Learn about the eigenfunctions of Sz and their role in quantum state projections
  • Explore the implications of fluctuating Hamiltonians in quantum systems
  • Investigate the mathematical techniques for averaging over random variables in quantum mechanics
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Quantum physicists, graduate students in physics, and researchers focusing on quantum mechanics and Hamiltonian dynamics will benefit from this discussion.

Niles
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Homework Statement


Hi

Say I have a Hamiltonian given by H = δSz acting on my system, where δ is a random variable controlled by some fluctuations in my environment. I have to show that if I start out with <Sx>=½, then the Hamiltonian will reduce <Sx> to

<Sx> = ½<cos(δt)>

where the <> around the cosine means averaged over all values of δ. What I would do is to use

<eiHtSx(0)e-iHt> = <Sx(t)>

but this seems very tedious. Am I on the right path here?


Niles.
 
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Isn't the easiest way to just get the eigenfunctions of Sz and then project Sx on that?
 
Niles said:
where the <> around the cosine means averaged over all values of δ. What I would do is to use

<eiHtSx(0)e-iHt> = <Sx(t)>

but this seems very tedious. Am I on the right path here?

Yes, but it shouldn't be a tedious computation. The expectation value of that time-evolved operator is just equal to x^H*Sx*x, where x is the time-evolved state vector. x is a 2x1 vector (written using the eigenvectors of H as a basis, because that's convenient) and Sx is a 2x2 matrix, so the computation shouldn't be too hard.
 

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