Is the Expectation Value Relation for QM Operators Valid?

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SUMMARY

The Expectation Value Relation for quantum mechanics (QM) operators, expressed as <a><b^&dagger> + <a^&dagger><b> = 2\operatorname{Re}[<a><b^&dagger>], is confirmed as valid in the discussion. The key point is that the conjugation applies to the operator b, resulting in <b^+> = <b>*. This establishes that the expectation values of these operators adhere to the properties of complex conjugation.

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Niles
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Homework Statement


Hi

My book uses the following in a calculation
<br /> \left\langle a \right\rangle \left\langle {b^\dagger } \right\rangle + \left\langle {a^\dagger } \right\rangle \left\langle b \right\rangle = 2\operatorname{Re} \left[ {\left\langle a \right\rangle \left\langle {b^\dagger } \right\rangle } \right]<br />
where a and b are QM operators. I agree with the relation z^*+z=\text{Re}(z) (for z a complex variable), but in the above case the conjugation is on the operator, not the expectation value itself. Is the relation valid?Niles.
 
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Ahh, I see it now. The relation is valid, as <b^+> = <b>*.
 

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