How Does a Moving Rectangular Loop Generate Current in a Magnetic Field?

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A rectangular loop of wire moving through a magnetic field generates current due to electromagnetic induction, as described by Faraday's law. The loop, measuring 15 cm by 2 cm and moving at 5 m/s in a magnetic field of 1.7 tesla, creates an electromotive force (emf) calculated using the formula emf = Blv. The current in the loop can be determined by dividing the emf by the loop's resistance of 0.8 ohms. Additionally, the magnetic force acting on the loop is influenced by the current flow and its direction relative to the magnetic field. Understanding these principles is essential for analyzing the behavior of the loop in the magnetic field.
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Pull a rectangular loop through a magnetic field
In the figure a rectangular loop of wire L = 15 cm long by h = 2 cm high, with a resistance of R = 0.8 ohms, moves with constant speed v = 5 m/s as shown. The moving loop is partially inside a rectangular region where there is a uniform magnetic field (gray area) and partially in a region where the magnetic field is negligibly small.

image: http://www.webassign.net/mi3/21.P.082-Fig20.92a.jpg

In the gray region, the magnetic field points into the page, and its magnitude is B = 1.7 tesla.



(c) What is the conventional current in the loop?


______A
(d) Which of the following are true? Check all that apply.
Because a current flows in the loop, there is a magnetic force on the loop.
The magnetic force only stretches the loop; the net magnetic force on the loop is zero.
The magnetic force on the loop is in the same direction as the velocity of the loop.

(e) What is the magnitude of the magnetic force on the loop?
________N


Thanks in advance.
 
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hi laser123! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
I'm stuck on C. I tried Fb=qvB then -Fb=qE then -Fb/q=E------->E*L=delta then deltaV/R=I
 
laser123 said:
I tried Fb=qvB then -Fb=qE then -Fb/q=E------->E*L=delta then deltaV/R=I

emf = Blv ? :wink:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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