How does a transistor act as an amplifier?

  • Thread starter Thread starter Aurelius120
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around the functioning of transistors, specifically NPN transistors, and their role as amplifiers. Participants explore the concept of treating a transistor as two diodes and question how current amplification occurs within the device.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the analogy of transistors as diodes and question the implications of this model. There are inquiries about the mechanisms of current amplification and the preservation of current ratios. Some participants express confusion about the role of the collector current and the effects of applying voltage across the transistor.

Discussion Status

The discussion is active, with participants raising various questions and exploring different interpretations of how transistors function. Some guidance has been offered through references to external resources, but there is no explicit consensus on the explanations provided.

Contextual Notes

Participants note the complexity of transistors and the potential for misunderstanding basic concepts. There is mention of the depletion zone at the NP junction and concerns about the implications of applying high voltage across the transistor.

Aurelius120
Messages
269
Reaction score
24
Homework Statement
How does a transistor work?
What is the explanation for amplification of current?
Relevant Equations
NA
I was reading about transistors. There was one good video.. It said to treat the NPN transistor as two diodes.
1000000174.jpg

And so I did. I remember learning that a forward biased diode can be treated as a cell that causes a potential drop equal to the barrier potential (while a reverse biased diode is an open circuit?)
1000000173.jpg

But I don't know how to proceed further?

And the video explained how the current is amplified a little too fast towards the end. I didn't understand it. From the circuit diagram and the explanation in the video I can somewhat see that the current will be increased. But I don't understand how? And definitely don't see how it increases by multiplication instead of addition?(Like why is the collector current something times the base current and not something plus the base current?)
 
Physics news on Phys.org
Sorry, I didn't watch that video. Transistors are a bit more complex than just two separate diodes as you've drawn in your schematic. The key point is that they share a very thin base region, so it's a single combined device. Honestly, there is a ton of information on the web explaining them. You'll do better to study a bit more than have me give a worse explanation than what's already out there. I would start here:

https://www.khanacademy.org/science...r-working-class-12-india-physics-khan-academy
 
Last edited:
  • Like
Likes   Reactions: Lord Jestocost and berkeman
DaveE said:
Sorry, I didn't watch that video. Transistors are a bit more complex than just two separate diodes as you've drawn in your schematic. The key point is that they share a very thin base region, so it's a single combined device. Honestly, there is a ton of information on the web explaining them. You'll do better to study a bit more than have me give a worse explanation that what's already out there. I would start here:

https://www.khanacademy.org/science...r-working-class-12-india-physics-khan-academy
So in this video he said that no matter how powerful a battery you apply across the N and N of the transistors, current will not flow unless a second battery is used across N and P because there is a depletion zone at one NP junction.

But the P-region of NPN is very thin so can't the charge carriers simply cross it when the applied voltage is large enough.

Also why is the ratio of the currents preserved? Why is it only dependent on the smaller voltage?
 
Last edited:
Aurelius120 said:
But the P-region of NPN is very thin so can't the charge carriers simply cross it when the applied voltage is large enough.
Sure. That is known as "letting the smoke out" of the transistor. Search on BVceo
 
berkeman said:
Sure. That is known as "letting the smoke out" of the transistor. Search on BVceo
You mean this video?
Here he says that if the collector circuit is open, all emitter current will flow through base and transistor will burn. But
If there is no collector current, then why will there be any amplification, the only current should be the small base current which flows through the emitter as well.
Why will attaching an open battery across the NN ends cause any effect on the circuit?
 
Aurelius120 said:
You mean this video?
Here he says that if the collector circuit is open, all emitter current will flow through base and transistor will burn. But
If there is no collector current, then why will there be any amplification, the only current should be the small base current which flows through the emitter as well.
Why will attaching an open battery across the NN ends cause any effect on the circuit?
Much like @DaveE I don't generally watch YouTube videos as references. If you have access to the Khan Academy, you can view their instruction video on transistors that Dave linked to. You can also read the Wikipedia article, especially the section on Simplified Operation:

https://en.wikipedia.org/wiki/Transistor

For me, one of the best images to keep in mind when thinking about how an NPN bipolar transistor works in the "Common Emitter" current amplifying configuration is using this graph:

1742757520950.png

https://www.electronics-tutorials.ws/transistor/tran_2.html

That is also a good tutorial to read through to understand why that plot is so instructive.
 
  • Like
Likes   Reactions: DaveE

Similar threads

Replies
5
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K