How does adding a constant Vo affect the potential in Griffith's Ex 3.8?

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SUMMARY

The discussion centers on the impact of adding a constant potential Vo to the electric potential V in Griffith's Example 3.8, which involves a grounded conducting sphere in a uniform electric field. The conclusion is that while the electric field at large distances remains unchanged, the inclusion of Vo modifies the potential outside the sphere. Specifically, the potential outside the sphere becomes V = EorPlcosθ + Vo, indicating that the boundary conditions are altered, affecting the overall potential distribution.

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Homework Statement


In the example of the grounded conducting sphere in the uniform electric field (Ex. 3.8), suppose we keep the constant of integration in V for large r, so that V -> EorPlcos\theta + Vo the electric field at large r is unchanged. Find V outside the sphere under these conditions. What is physically different?

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The Attempt at a Solution


I think this is the same problem. I was just wondering if l = 2? And what will happened to the Vo??
 
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The boundary condition is changed this will change the outcome when calculating the field outside
 
If I understand your question correctly, you just have to add V_0 to the previous answer for the potential anywhere.
 

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