How does air resistance affect falling objects of different weights?

  • Context: High School 
  • Thread starter Thread starter gmxplode
  • Start date Start date
  • Tags Tags
    Air Friction Gravity
Click For Summary
SUMMARY

The discussion clarifies that in a vacuum, all objects fall at the same rate regardless of their mass, as demonstrated by the example of a bowling ball and a feather. However, in real-world scenarios, air resistance significantly affects falling objects, making the shape and surface area critical factors. The formula for calculating the time of free fall in a vacuum is provided as t = √(2d/a), where 'd' is the distance and 'a' is the acceleration due to gravity (9.8 m/s²). Adjusting for air resistance complicates the calculation, requiring additional considerations beyond this basic formula.

PREREQUISITES
  • Understanding of basic physics concepts, particularly gravity and free fall.
  • Familiarity with the formula for free fall time: t = √(2d/a).
  • Knowledge of air resistance and its impact on falling objects.
  • Ability to convert units between feet and meters for calculations.
NEXT STEPS
  • Research the effects of air resistance on different shapes and sizes of objects.
  • Learn how to derive the free fall time formula and its applications.
  • Explore numerical methods for calculating the impact of air resistance on falling objects.
  • Investigate real-world applications of free fall physics in engineering and safety design.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of falling objects and the effects of air resistance in real-world scenarios.

gmxplode
Messages
10
Reaction score
0
gravity and air friction?

hey guys i am little confused about how two objects will react each having different weight when it is allowed to fall from a building of 20 floors...for eg if 1 is weighing 100 kg and other one 45 kg so 100 kg will touch the ground first but how much time will an object weighing 50kg take to touch the ground from a height of 300 feet.and consider object's height to be around 6 feet.
 
Physics news on Phys.org


Actually that is incorrect to say that the heavier object will hit the ground first.

If we consider that you drop them in a vacuum (and the base of the objects are at the same height, so size of objects don't matter)
then 2 objects will hit the ground at the exact same time regardless of their mass.
So yes, in vacuum a bowling ball and a feather will fall at the same rate.

Now.. if we try to consider more realistic scenarios, you will have air resistance. But you still cannot say that a heavier object will hit the ground first, it completely depends on the shape of an object.
So a bowling ball obviously hits the ground before a feather.
But what about a bowling ball strapped to a parachute compared to a pebble?
The pebble is lighter but hits the ground before the bowling ball+parachute.So in the ideal situation (in vacuum) all objects fall at the same rate (near earth) regardless of size and shape. The only thing that matters is the height you drop them from.
 


spacelike said:
Actually that is incorrect to say that the heavier object will hit the ground first.

If we consider that you drop them in a vacuum (and the base of the objects are at the same height, so size of objects don't matter)
then 2 objects will hit the ground at the exact same time regardless of their mass.
So yes, in vacuum a bowling ball and a feather will fall at the same rate.

Now.. if we try to consider more realistic scenarios, you will have air resistance. But you still cannot say that a heavier object will hit the ground first, it completely depends on the shape of an object.
So a bowling ball obviously hits the ground before a feather.
But what about a bowling ball strapped to a parachute compared to a pebble?
The pebble is lighter but hits the ground before the bowling ball+parachute.


So in the ideal situation (in vacuum) all objects fall at the same rate (near earth) regardless of size and shape. The only thing that matters is the height you drop them from.

i completely agree with your point.but what if i want to know in how much time a normal person will reach the ground from a height of 270 feet..can you just calculate or tell any formula to calculate that?
 


You can do that, it's actually quite simple if you assume they are falling in a vacuum (zero air resistance)

t=\sqrt{\frac{2d}{a}}
where a=9.8m/s^{2} make sure to use consistent units, so if you want to use d=270ft you'd have to convert this to meters, or convert a into feet per second squared.

If you want me to show you from where we derive that equation just ask.

Also, if you were asking for how to find the time if we DO have air resistance, then there's a bit more to it.

Sorry for the short answers I have to take care of something right now. But I think I could help you if you are interested in the air resistance problem.
 


Using that formula t = root 2D/a i was able to achieve time that is 4.09 seconds but that is when only gravity is affecting but in real world there is some air resistance so how can we find that and adjust in above formula
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
781
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 30 ·
2
Replies
30
Views
5K
  • · Replies 3 ·
Replies
3
Views
16K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 26 ·
Replies
26
Views
9K
  • · Replies 6 ·
Replies
6
Views
3K