The discussion revolves around how an object's velocity changes over time during constant acceleration, particularly in the context of gravitational acceleration. Participants explore the relationship between velocity, time, and acceleration, as well as the implications of these concepts on a velocity-time graph.
Participants express varying levels of understanding regarding the representation of velocity on a graph and the implications of constant acceleration. There is no consensus on the clarity of the initial question, and multiple interpretations of the concepts are present.
Some assumptions about the nature of acceleration and the conditions under which velocity is measured may not be fully articulated, leading to potential misunderstandings. The discussion does not resolve these ambiguities.
Yes, usually written v=\frac{ds}{dt}.skm22 said:Speed is the change in distance over change in time
Yes. Acceleration is the change of velocity over change in time, usually written a=\frac{dv}{dt}. So, if a is constant, v=v_{0}+a_{0}\cdot t (constant acceleration or deceleration). The standard example: you hold an object at height h and drop it. Then gravity will impose a constant acceleration on it and since it started with velocity 0, you have v=g\cdot t (at least until the object hits the ground).skm22 said:When something is accelerating at a constant rate, each speed on the velocity-time graph is only present at one specific point in time.