Where is nuclear binding energy stored?

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Homework Help Overview

The discussion revolves around the concept of nuclear binding energy, specifically focusing on where this energy is stored within the context of nuclear physics. The original poster expresses confusion regarding conflicting explanations found in various sources about the nature of binding energy and its relationship to the nucleus.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to reconcile different definitions and explanations of nuclear binding energy, questioning whether it is stored within the nucleus or released to the surroundings. Some participants explore the implications of binding energy being negative and discuss the relationship between binding and unbinding processes.

Discussion Status

Participants are actively engaging with the original poster's confusion, providing insights into the nature of binding energy and its potential storage. There is a recognition of the complexity of the topic, with various interpretations being explored without reaching a definitive consensus.

Contextual Notes

There appears to be a reliance on multiple textbooks and online sources, which may contribute to the confusion regarding the definitions and explanations of nuclear binding energy. The discussion highlights the need for clarity on the concepts of binding and unbinding energy in nuclear systems.

Arun Muthu
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I understand that the difference in mass between the protons and neutrons and the nucleus itself is called the mass defect, and that this mass defect is converted into nuclear binding energy. What seems to confuse me is where this energy is actually stored. I've been reading 4-5 different textbooks and several sources online but they seem to give conflicting perspectives on the matter. Some say that they are stored within the nucleus itself, whilst others say that they are "released", i.e. transferred to the surroundings. The latter makes more sense to me, as nuclear binding energy is officially defined as the amount of energy required to break apart the protons and neutrons and hence completely disassemble a nucleus.

I'm genuinely confused and would appreciate any help.
 
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Binding energy in an attractive potential is negative, so a bound system has less energy than its unbound components. This means that in the process of binding there is excess energy being released to the environment. Similarly, unbinding requires a supply of external energy.

You could turn the argument around, and using the bound state as the baseline, ask where is the added energy stored when you unbind the components of the nucleus. In which case you could say that the extra energy you supplied is stored in the field (its potential energy).

If nuclear forces are too far removed from your intuitions, try visualising the same thing using gravity. All these concepts apply there accordingly.
 
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Bandersnatch said:
Binding energy in an attractive potential is negative, so a bound system has less energy than its unbound components. This means that in the process of binding there is excess energy being released to the environment. Similarly, unbinding requires a supply of external energy.

You could turn the argument around, and using the bound state as the baseline, ask where is the added energy stored when you unbind the components of the nucleus. In which case you could say that the extra energy you supplied is stored in the field (its potential energy).

If nuclear forces are too far removed from your intuitions, try visualising the same thing using gravity. All these concepts apply there accordingly.
 
Well explained!
 

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