How Does Capacitance Change with Angle in Non-Parallel Plate Capacitors?

[Fusilli_Jerry89]

Homework Statement

A capacitor has square plates, each of side a, making an angle theta with each other. Shown that for small theta the capacitance is given by: C = [(epsilon)(a^2)/d][1-(a(theta)/2d].

Homework Equations

C = q/V
gauss' law

The Attempt at a Solution

I see how you can divide up the strip into N segments each with length a/N. But how do u get the capacitance for each strip to be C = (epsilon)a(deltax)/y ? I know how to do the rest and I know for sure that that's the right way to do it, but how do u get the capacitance for each strip?)

 

[michalll]

See that C = $$\epsilon$$*S/d, in your case for each strip S = a*dx and d = y.

 

[omeraz100]

I'm also troubled with this question, I know it has been a long time, but maybe one of you can explain me the answer?

Omer